Which of the following quadratic equations has no real solution?

1 answer:

8 0

D. You define if a quadratic equation has an answer or not by the delta (the calculation inside the sqrt on the quadratic formula). So you simply calculate b^2 -4ac, if the answer is equal or greater than zero there is a solution, if not there isn’t. (Consider ax^2+bx+c) Hope it helped :)

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For which values of the parameter B the following system admits a unique solution [ 1 b 1-b 2 2 0 2–2B 4 0] [x y z] = [1 2 0]

photoshop1234 [79]

Answer: β ≠ ±1

Step-by-step explanation: For a system of equations to have an unique solution, its determinant must be different from 0: det |A| ≠ 0. So,

det $\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right]$ ≠ 0

Determinant of a 3x3 matrix is calculated by:

det $\left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right]\left[\begin{array}{ccc}1&\beta\\2&2\\2-2\beta&4\end{array}\right]$