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2 years ago

What is the domain of the function y = √x + 4 ?

Mathematics

1 answer:

puteri [66]2 years ago

8 0

Hello from MrBillDoesMath!

Answer:

Domain: x >=0 for both cases

Discussion:

Assuming we are dealing with real valued functions, the domain of

y = x^(1/2) +4

is the set of all "x" such that x>= 0 (so we are taking the square root of a positive, or zero, real number)

The domain of x^(1/2) +6 -7 is the same as for the last function and for the same reason.

Thank you,

MrB

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$Radius = 6cm$

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

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Required

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Factorize:

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$0=2\pi (-\frac{432}{r^2} + 2r)$

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Divide through by 2

$r^3 = 216$

Take cube roots of both sides

$r = \sqrt[3]{216}$

$r = 6$

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$h = \frac{432}{r^2}$

$h = \frac{432}{6^2}$

$h = \frac{432}{36}$

$h = 12$

Hence, the dimension that requires the least amount of material is when

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