What is the domain of the function y = √x + 4 ?
1 answer:
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Answer:
The equation of the graph below is y = 0.5 csc[0.5(x + π/2)] - 1 ⇒ 3rd answer
Step-by-step explanation:
* Lets revise the trigonometry transformation
- If the equation is y = A csc(B(x + C)) + D
# Amplitude is A
- The Amplitude is the height from the center line to the peak .
Or we can measure the height from highest to lowest points and
divide that by 2
# period is 2π/B
- The Period goes from one peak to the next
# phase shift is C (positive is to the left)
- The Phase Shift is how far the function is shifted horizontally
from the usual position.
# vertical shift is D
- The Vertical Shift is how far the function is shifted vertically from
the usual position.
- If y = csc(x)
∴ A = 1 , B = 1 , C = 0 , D = 0
- That means the amplitude is 1, the period is 2π, no phase shift
or vertical shift
* Now lets solve the problem
- From the graph
# The amplitude = (-0.5 - -1.5)/2 = 0.5
∴ A = 0.5
# The period is from 2.5π to -1.5π
∴ The period is 4π
∵ The period = 2π/B
∴ 4π = 2π/B ⇒ by cross multiplication
∴ B = 2π/4π = 1/2 = 0.5
* There is only one answer has A = 0.5 and B = 0.5
∴ y = 0.5 csc[0.5(x + π/2)] - 1
* The equation of the graph below is 0.5 csc[0.5(x + π/2)] - 1
* For more understand look to the color graph
- The blue graph is y = csc(x)
- The green graph is y = 0.5 csc[0.5(x + π/2)] - 1
