For a data point measured as y = 3.5 for an x value of x = 1.2, the residual would be 0.1
For given question,
we have been given an equation 2x + 1 that represents an equation for a trendline to the data.
General formula with residual is y = 2x + 1 + r, where r is a residual.
We need to find the residual for a data point measured as y = 3.5 for an x value of x = 1.2
We substitute given values of x and y in the residual equation
y = 2x + 1 + r
For y = 3.5 and x = 1.2,
⇒ 3.5 = 2(1.2) + 1 + r
⇒ 3.5 = 2.4 + 1 + r
⇒ r = 3.5 - 3.4
⇒ r = 0.1
Therefore, for a data point measured as y = 3.5 for an x value of x = 1.2, the residual would be 0.1
Learn more about the residual here:
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Answer:
a = 1.5
Step-by-step explanation:
Given:
-3√123 = -2√123 x ------
Assume;
Blank = a
Computation:
a = -3√123 / -2√123
a = 3 / 2
a = 1.5
Answer:
b=4 makes the equation a perfect square.
Step-by-step explanation:
As long as you factorize out the equation, you'll get a result of (x+2)^2. This multiplied using foil gives you, x^2 + 2x + 4. Making it a perfect square. You could also have -2 = b which makes a perfect square, but that's not in the options.
