Given:
Quadrilateral ABCD is inscribed in a circle P.
To find:
Which statement is necessarily true.
Solution:
Quadrilateral ABCD is inscribed in a circle P.
Therefore ABCD is a cyclic quadrilateral.
In cyclic quadrilateral, opposite angles form a supplementary angles.
⇒ m∠A + m∠C = 180° --------- (1)
⇒ m∠B + m∠D = 180° --------- (2)
By (1) and (2),
⇒ m∠A + m∠C = m∠B + m∠D
This statement is necessarily true for the quadrilateral ABCD in circle P.
Answer:
1. Not proportional 2. is proportional. For 3, 4, 5, and 6 just plot them.
Step-by-step explanation:
For 1, y intercept/x intercept is not 0 when you graph, thus not proportional. Number 2 is, thus proportional. For 3, 4, 5, and 6 you would plot them accordingly. So for (-5, -2) Start as 0,0 and go 5 to the left as it's negative, and 2 down as it is also negative. Do the same for others.
When converting English phrases into mathematical expressions/equations, we do things from left to right. That is why it's 4 - 20 instead of 20 - 4.
This rule is applied to division as well.
Answer:
2
Step-by-step explanation:
(x,y)
Answer:
x=-9
Step-by-step explanation:
5x+1=7x+19
1 = 7x-5x +19
1-19 = 2x
-18/2 = x
x = -9
Hope this helps!
Please mark brainliest if you think I helped! Would really appreciate!
