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pickupchik [31]
3 years ago
14

For the following exercises, evaluate the function at the indicated values: f (−3); f (2); f (−a); −f (a); f (a + h).

Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

5. f(x) = -2x² + 3x  

f(-3) = -2(-3)² + 3(-3) = -27

f(2) = -2(2)² + 3(2) = -2

f(-a) = -2(-a)² + 3(-a) = -2a² - 3a

-f(a) = -[-2a² + 3a] = 2a² - 3a

f(a + h) = -2(a + h)² + 3(a + h) = -2(a² + 2ah + h²) + 3a + 3h = -2a² - 4ah - 2h² + 3a + 3h

6. f(x) = 2|3x - 1|

f(-3) = 2|3(-3) - 1| = 2*10 = 20

f(2) = 2|3(2) - 1| = 2*5 = 10

f(-a) = 2|3(-a) - 1| = 2|-3a - 1|

-f(a) = -(2|3a - 1|) = -2|3a - 1|

f(a + h) = 2|3(a + h) - 1| = 2|3a + 3h - 1|

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snow_tiger [21]

<em>Greetings from Brasil...</em>

According to the annex, we note that

1 qt = 1 quart = 0.95L

To solve this problem, just apply some rules of 3.....

1st - how many qt's are in 15.5 cups

  qt                 cup

   1   ----------     4

   X  ----------   15.5

4 · X = 1 · 15.5

4X = 15.5

X = 15.5 ÷ 4

X = 3.875qt

Last rule of 3 to know how many liters there are in 3.875qt:

  qt                       litres

   1         ----------    0.95

3.875    ----------      Y

1 · Y = 0.95 · 3.875

<h2>Y = 3.68L</h2>

In a day a young man should drink 3.68L of water

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3 years ago
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sergey [27]
Equation 1
y=x-0.7

equation 2
x=y+0.7

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Your answer is 0.25, bro
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What is the answer to this 2^2^2^2^0?
alexandr402 [8]
The awnser is 156 so yeah
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