Answer:
Population in 2100 is 17.99 billion.
Step-by-step explanation:
The population of the world in 2020 = 7.8 billion.
The growth rate = 1.05%
Now find the population after 2100. Use the below formula to find the population.
Population in 2100 = Population of 2020 (1 + growth rate)^n
Population in 2100 = 7.8 (1 + 0.0105)^80
Population in 2100 = 17.99 billions.
Now, find the growth rate in 2100.
dN/dt = [r N (K – N) ] / K
r = Malthusian parameter
K = carrying capacity.
Now divide both sides by K, now x = N/K then do the differential equation.
dx/dt = r x ( 1- x)
Now integrate, x(t) = 1/ [ 1 + (1/x – 1) c^-rt
From the first equation = dN/dt = (13 – 7.8) / 80 = (r × 7.8×(13 – 7.8) / 12
0.065 = (r × 7.8× 5.2) / 12
0.065 = r × 3.38
r = 1.92%
Answer: False
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Explanation: Eukaryotes along with some prokaryotes also perform the process of photosynthesis. Photosynthesis needs chloroplast and it is also found in some of the prokaryotes.
Prokaryotes are primitive cells but they do have organelles like mitochondria and chloroplast.
Photosynthesis is the process by which glucose is made in the presence of sunlight out of which oxygen is released into the environment and carbon dioxide from the environment is used.
Answer:
What the english?
Step-by-step explanation:
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Answer: The numbers are: " 21 " and " 105 " .
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Explanation:
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Let "x" be the "one positive number:
Let "y" be the "[an]othyer number".
x = 1/5 (y)
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Given that the difference of the two number is "84" ; and that "x" is (1/5) of "y" ; we determine that "x" is smaller than "y".
So, y − x = 84 .
Add "x" to each side of this equation; to solve for "y" in terms of "x" ;
y − x + x = 84 + x ;
y = 84 + x ;
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So, we have:
x = (1/5) y ;
and: y = 84 + x ;
Substitute "(1/5)y" for "x" ; in "y = 84 + x " ; to solve for "y" ;
y = 84 + [ (1/5)y ]
Subtract " [ (1/5)y ] " from EACH SIDE of the equation ;
y − [ (1/5)y ] = 84 + [ (1/5)y ] − [ (1/5)y ] ;
to get:
[ (4/5)y ] = 84 ;
↔ (4y) / 5 = 84 ;
→ 4y = 5 * 84 ;
Divide EACH SIDE of the equation by "4" ;
to isolate "y" on one side of the equation; and to solve for "y" ;
4y / 4 = (5 * 84) / 4 ;
y = 5 * (84/4) = 5 * 21 = 105 .
y = 105 .
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Now, plug "105" for "y" into:
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Either:
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x = (1/5) y ;
OR:
y = 84 + x ;
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to solve for "x" ;
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Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
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Start with:
x = (1/5)y
→ (1/5)*(105) = 105 / 5 = 21 ; x = 21 ;
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So, x = 21; y = 105 .
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Now, let us see if this values hold true in the other equation:
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y = 84 + x ;
105 = ? 84 + 21 ?
105 = ? 105 ? Yes!
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The numbers are: " 21 " and "105 " .
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Without the original equation, it's impossible to answer that question. I'm sorry.
