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Furkat [3]
3 years ago
10

The masses to the nearest 0.5 kg of two parcels are 1.5 kg and 2.5 kg .calculate the lower and upper bounds of their combined ma

ss.​
Mathematics
1 answer:
Yanka [14]3 years ago
6 0

Answer:

(3.5, 4.5)

Step-by-step explanation:

The masses have a total margin of 0.5 kg, or ±0.25 kg.

The mass of the first parcel is 1.5 kg ± 0.25 kg.

The mass of the second parcel is 2.5 kg ± 0.25 kg.

The combined mass is:

(1.5 kg + 2.5 kg) ± (0.25 kg + 0.25 kg)

4 kg ± 0.5 kg

So the lower bound is 3.5 kg and the upper bound is 4.5 kg.

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A coach is assessing the correlation between the number of hours spent practicing and the average number of points scored in a g
cricket20 [7]

Answer:

a) r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

b) m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

c) For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

Step-by-step explanation:

We have the following data:

Number of hours spent practicing (x) 0 0.5 1 1.5 2 2.5 3 3.5 4

Score in the game (y) 5 8 11 14 17 20 23 26 29

Part a

The correlation coefficient is given:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=9 \sum x = 18, \sum y = 153, \sum xy = 396, \sum x^2 =51, \sum y^2 =3141  

r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=51-\frac{18^2}{9}=15  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=396-\frac{18*153}{9}=90  

And the slope would be:  

m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

Part c

For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

5 0
3 years ago
There were 324 adults surveyed. Among the participants, the mean number of hours of sleep each night was 7.5 and the standard de
kirill [66]
0.17 sense you have to round it to the nearest hundreth


5 0
3 years ago
Read 2 more answers
12.917 rounded to the nearest ones
adelina 88 [10]
I am pretty sure the answer is 13
6 0
4 years ago
Read 2 more answers
I need help with this someone!!
Alex

Answer:

Do u have answer choices?

4 0
4 years ago
Read 2 more answers
3 increased by the product of 4 and a number is equal to the same number decreased by 6. What is the number
nasty-shy [4]

Answer:

1

Step-by-step explanation:


8 0
3 years ago
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