Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
The answer could be -120 in a simplified form
Answer:
3
Step-by-step explanation:
There is a 1/4 chance of landing on an x. If you multiply 4*3 you get 12 (The total amount of parts) but since you multiplied 4 by 3 you also have to multiply 1 by 3, so that would give you 3/12 meaning that 3 parts are labeled "x"
Answer:
i think it is 5 in not sure hope this had helped
Step-by-step explanation: