2 years ago

If 3^2x+1=3^x+5 what is the value of x?

2 answers:

6 0

Did you mean this? 3^2x+1=3^x+5 => 3^(2x+1) = 3^(x+5)? If so, then 2x+1 is necessarily equal to x+5, so that 2x+1=x+5. Thus, x = 4 (answer).

Those parentheses are not optional; they must be part of your problem statement and solution.

lara [203]2 years ago

6 0

Answer:

Step-by-step explanation:

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3 years ago

what is the simplified form of the following expression? Assume X 0 and y 0. 2(^4 sqrt 16 x) -2(^4 sqrt 2y )+3 (^4 sqrt 81x ) -4

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For this case we have the following expression:

$2(\sqrt[4]{16x})-2(\sqrt[4]{2y})+3(\sqrt[4]{81x})-4(\sqrt[4]{32y})$

Rewriting the numbers within the roots we have:

$2(\sqrt[4]{2*2*2*2x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3*3*3*3x})-4(\sqrt[4]{2*2*2*2*2y})$

Then, by properties of powers we have:

$2(\sqrt[4]{2^4x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3^4x})-4(\sqrt[4]{2^42y})$

Then, by radical properties we have:

$2(2\sqrt[4]{x})-2(\sqrt[4]{2y})+3(3\sqrt[4]{x})-4(2\sqrt[4]{2y})$

Rewriting the expression we have:

$4\sqrt[4]{x}-2\sqrt[4]{2y}+9\sqrt[4]{x}-8\sqrt[4]{2y}$

Finally, adding similar terms we have:

$(4+9)\sqrt[4]{x}-(2+8)\sqrt[4]{2y}$

$13\sqrt[4]{x}-10\sqrt[4]{2y}$

Answer:

The simplified form of the expression is:

$13\sqrt[4]{x}-10\sqrt[4]{2y}$

7 0

2 years ago

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