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noname [10]
3 years ago
11

In the 3-month period November 1, 2014, through January 31, 2015, Hess Corp. (HES) stock decreased from $80 to $64 per share, an

d Exxon Mobil (XOM) stock decreased from $96 to $80 per share.† If you invested a total of $22,240 in these stocks at the beginning of November and sold them for $18,080 3 months later, how many shares of each stock did you buy?
Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0

Answer: 170 HES and 90 XOM

Hi! Let's say you bought A HES shares, and B XOM shares. As you invested $22,240, yo have that:

22,240 = A*80 + B*96     (80 and 96 are the initial prices)

3 months later those prices decreased to 64 and 80, and you sold your shares at those prices, then:

18,080 = 64*A + 80*B

This is a system of two linear equations and two unkowns A, B. You can solve it getting A from first equation:

A = (22,240-B*96)/80

And then replacing A into the second equation you can find the value of B. Then replacing B in the third equation you get A.

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Y+1=3/4(x+7) standard form
Bad White [126]

Answer:

3x - 4y= -17 or slope intercept form is y= \frac{3}{4}x+\frac{17}{4}

Step-by-step explanation:

Use the Ax+By=C equation

3 0
3 years ago
Pwease help 1 more quesiton
Salsk061 [2.6K]
The answer is (2,-6) look at the picture to see how to do it

7 0
3 years ago
Read 2 more answers
Paul owns a mobile wood-fired pizza oven operation. A couple of his clients complained about his dough at a recent catering, so
Makovka662 [10]

Answer: B. Do not reject H0, we cannot conclude the proportion of customer complaints is more for the old dough

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the old and the new dough players. The population proportions of customer complaints with the old and new dough would be p1 and p2

P1 - P2 = difference in the proportion of customer complaints with the old and new dough.

The null hypothesis is

H0 : p1 ≥ p2

pm - pw ≥ 0

The alternative hypothesis is

Ha : p1 < p2

p1 - p2 < 0

it is a left tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For old dough

x1 = 6

n1 = 385

P1 = 6/385 = 0.016

For new dough,

x2 = 16

n2 = 340

P2 = 16/340 = 0.047

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (6 + 16)/(385 + 340) = 0.03

1 - pc = 1 - 0.03 = 0.97

z = (Pm - Pw)/√pc(1 - pc)(1/nm + 1/nw)

z = (0.016 - 0.047)/√(0.03)(0.97)(1/385 + 1/340) = - 0.031/√0.00553857907

z = - 0.42

Since it is a left tailed test, we would find the p value for the area to the left of the z score. From the normal distribution table,

p value = 0.337

For a 95% confidence level, the significant level, alpha is

1 - 0.95 = 0.05

Since 0.05 < 0.337, we would accept the null hypothesis

Therefore, Do not reject H0, we cannot conclude the proportion of customer complaints is more for the old dough

7 0
3 years ago
The smiths previously lived in a house that had 1450 sq ft of space. The sq ft of their new home is 3800 sq ft. What is the perc
lana66690 [7]

Answer:

162.1%

Step-by-step explanation:

Given that:

Size of previous living space = 1450 sq ft

Size of new living space = 3800 sq ft

% increase in living space ;

Increase in living space = 3800 - 1450 = 2350 sq feet

(Increase / previous size) * 100%

(2350 / 1450) * 100%

1.6206 * 100%

= 162.06%

= 162.1%

5 0
2 years ago
What would be the answer
sashaice [31]

Answer:

I think It's option (B) 45

Step-by-step explanation:

But I am not sure It's correct or not

I hope It's helpful

6 0
2 years ago
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