Find the slope of the line passing through the points (-5,1) and (2,4).

Mathematics

1 answer:

Leno4ka [110]2 years ago

7 0

Answer:

<h3> $\boxed{ \bold{ \huge{ \boxed{ \sf{ \frac{3}{7} }}}}}$ </h3>

Step-by-step explanation:

Let the points be A and B

A ( -5 , 1 ) ⇒( x₁ , y₁ )

B ( 2 , 4 )⇒( x₂ , y₂ )

Finding the slope of the line passing through these Points

Slope = $\sf{ \frac{y2 - y1}{x2 - x1} }$

plug the values

⇒ $\sf{ \frac{4 - 1}{2 - ( - 5)} }$

We know that $\sf{( - ) \times ( - ) = ( + )}$

⇒ $\sf{ \frac{4 - 1}{2 + 5} }$

Subtract 1 from 4

⇒ $\sf{ \frac{3}{2 + 5} }$

Add the numbers

⇒ $\sf{ \frac{3}{7} }$

Hope I helped!

Best regards!!

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professor190 [17]

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8 0

3 years ago

Read 2 more answers

-6-5

tankabanditka [31]

The equation of the line that is parallel to the given line and passes through the point (-2,2) is:

$y = \frac{x}{5} + \frac{12}{5}$

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

When two lines are parallel, they have the same slope. In this problem, the given line passes through (-5,-4) and (0,-3), hence the slope is:

m = (-3 - (-4))/(0 - (-5)) = 1/5.

Hence the equation is:

$y = \frac{x}{5} + b$