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2 years ago

What is the value for x when using algebra tiles to solve the equation x+1=-x+(-5)?

Mathematics

2 answers:

lesya [120]2 years ago

4 0

x + 1 = -x + (-5)

2x + 1 = -5

2x = -6

x = -3

Lerok [7]2 years ago

4 0

Answer: The value of x is -3

Step-by-step explanation: We want to solve the equation x+1=-x+(-5)

the first thing we want to do is isolate x, for doing this we may add x in both sides of the eqution, to remove the x therm in the right side:

x+1 +x =-x+(-5) + x

2x + 1 = - 5

now we can subtract 1 in both sides, to remove the 1 in the left side.

2x + 1 - 1 = -5 - 1

2x = - 6

now we can divide both sides by 2, with the objective of remove the factor 2 in the left side

2x/2 = -6/2

x = -3

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Which statement describes the effect on the parabola f(x)=2x•x-5x+3 when changed to f (x)= 2x•2-5x+1

o-na [289]

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The parabola is translated down 2 units.

Step-by-step explanation:

You have the parabola f(x) = 2x² – 5x + 3

To change this parabola to f(x) = 2x² - 5x + 1, you must have performed the following calculation:

f(x) = 2x² – 5x + 3 -2= 2x² - 5x + 1 Expresion A

The algebraic expression of the parabola that results from translating the parabola f (x) = ax² horizontally and vertically is g (x) = a(x - p)² + q, translating in the same way as the function.

If p> 0 and q> 0, the parabola shifts p units to the right and q units up.
If p> 0 and q <0, the parabola shifts p units to the right and q units down.
If p <0 and q> 0, the parabola shifts p units to the left and q units up.
If p <0 and q <0, the parabola shifts p units to the left and q units down.

In the expression A it can be observed then that q = -2 and is less than 0. So the displacement is down 2 units.

This can also be seen graphically, in the attached image, where the red parabola corresponds to the function f(x) = 2x² – 5x + 3 and the blue one to the parabola f(x) = 2x² – 5x + 1.

In conclusion, the parabola is translated down 2 units.