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3 years ago

What is the value for x when using algebra tiles to solve the equation x+1=-x+(-5)?

Mathematics

2 answers:

lesya [120]3 years ago

4 0

x + 1 = -x + (-5)

2x + 1 = -5

2x = -6

x = -3

Lerok [7]3 years ago

4 0

Answer: The value of x is -3

Step-by-step explanation: We want to solve the equation x+1=-x+(-5)

the first thing we want to do is isolate x, for doing this we may add x in both sides of the eqution, to remove the x therm in the right side:

x+1 +x =-x+(-5) + x

2x + 1 = - 5

now we can subtract 1 in both sides, to remove the 1 in the left side.

2x + 1 - 1 = -5 - 1

2x = - 6

now we can divide both sides by 2, with the objective of remove the factor 2 in the left side

2x/2 = -6/2

x = -3

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Rename 2/5 as a percent_______________________

loris [4]

It can be helpful to remember that "%" is just a shorthand way to write "/100" (divided by 100, or per 100, or per cent). ("Cent" is often used to refer to 100 or 1/100. A "cent" is 1/100 of a dollar, or 1/100 of an acre, for example. A <em>cent</em>ury is 100 years.)

Make the denominator of your fraction be 100. Multiply numerator and denominator by 20/20.

(2/5)×(20/20) = 40/100 = 40%

You can also get there via decimals.

... 2/5 = 0.4 = 0.40 (40 hundredths) = 40/100 (40 hundredths) = 40%

Or, you can multiply by 100%.

... (2/5)×(100%) = (200/5)% = 40%

7 0

3 years ago

If Luke pushes his sister in a wagon down the driveway that is 14 meters long and it takes 22 Newtons of force, how much work di

erica [24]

Hello!

The answer is:

Luke did a work of 308N.m or 308 Joules.

When a force is applied on a object making it to move covering a distance we call it "work". The movement caused by the force, will follow the same direction that the force.

We can calculate the work done by using the following equation:

$Work=Force*distance*Cos(\alpha)$

Where,

Work is the transferred energy.

Force, is the force applied to the object.

Distance, is the distance covered due to the applied force.

α, is the angle at the work is done.

We are given the following information to calculate the work done:

$Force=22N\\Distance=14m$

So, substituting the given information into the equation to calculate work, we have:

$Work=Force*distance\\Work=22N*14m=308N.m$

Hence, we have that Luke did a work of 308N.m or 308 Jouls.

Have a nice day!

3 0

3 years ago

How do you compare 4/15 and 3/4?

slavikrds [6]

Find the least common denominator or LCM of the two denominators. LCM of 4 and 15 is 60. 4x15= 60 34=3x154x15=4560 3/4 is bigger

6 0

2 years ago

Write the monomial in standard form. name it's coefficient and identify its degree.

Hunter-Best [27]

Answer:

$Standard\ Form = {3n^2} m^{-2}$

Step-by-step explanation:

Given

$\frac{2}{3m^2n} * 4.5n^3$

Required

Write in Standard Form

To start with; the two monomials have to be multiplied together;

$\frac{2}{3m^2n} * 4.5n^3$

$Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}$

Split the numerator and the denominator

$Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}$

Multiply Like terms

$Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}$

Divide 9 by 3 to give 3

$Standard\ Form = \frac{3 * n^3}{m^2 * n}$

Divide n³ by n to n²

$Standard\ Form = \frac{3 * n^2}{m^2 }$

Split fraction

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$

From laws of indices;

$\frac{1}{a^n} = a^{-n}$

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$ becomes

$Standard\ Form = {3 * n^2} * m^{-2}$

Multiply all together

$Standard\ Form = {3n^2} m^{-2}$

5 0

3 years ago

Find the average rate of change of f(x) = 4x² – 3 from 3 to 9.

Lina20 [59]

Answer:

Step-by-step explanation:

Given:

$f(x) = 4x^2 - 3$

Required:

Average range of change from 3 to 9

SOLUTION:

Step 1:

Find f(3) and f(9):

To find f(3), replace x with 3 in the given function

$f(3) = 4(3)^2 - 3$

$f(3) = 4(9) - 3$

$f(3) = 36 - 3$

$f(3) = 33$

To find f(9), replace x with 9 in the given function

$f(9) = 4(9)^2 - 3$

$f(9) = 4(81) - 3$

$f(9) = 324 - 3$

$f(9) = 321$

Average rate of change = $\frac{f(b) - f(a)}{b - a}$

Where,

$a = 3, f(a) = 33$

$b = 9, f(b) = 321$

Plug in the values into the formula for average rate of change.

$= \frac{321 - 33}{9 - 3}$

$= \frac{288}{6}$

$= 44$

Average rate of change = 44

3 0

3 years ago