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Ostrovityanka [42]
3 years ago
6

73,104 is 192% of what number?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
8 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em>

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Help help help if u can answer this I’ll mark u brainliest (6) (the one in the middle)
Hoochie [10]

You just have to plug in each thing:

So f(0):

3(0)^2 - 4 = -4

so its not A

f(-2) and f(2):

3(-2)^2 - 4

3(2)^2 -4

now we don't even have to calculate these, anything to the power of an even number is a positive number so -2^2 and 2^2 both equal 4

B is correct, so you can do the others if you want to check, but if B is true the others shouldn't be true.

4 0
3 years ago
Evaluate he expression for x=4​
hoa [83]

Answer:

41

Step-by-step explanation:

Step 1:

12x - 7          Equation

Step 2:

12 ( 4 ) - 7       Input x value

Step 3:

48 - 7       Multiply

Answer:

41        Subtract

Hope This Helps :)

8 0
3 years ago
Read 2 more answers
Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord
andrew-mc [135]
Consider the circle with center X, as shown in the figure. 

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is  

\sqrt{ XB^{2}- CB^{2}} = \sqrt{ 10^{2}- CB^{6}}= \sqrt{100-36}= \sqrt{64}=8 units.


Answer: 8 units

7 0
3 years ago
Please help IM OFFERING ALOT OF POINTS !!!!
VMariaS [17]

Answer:

cos 2Ф = - 161/289 , tan 2Ф = - 240/161

Step-by-step explanation:

* Lets explain how to solve the problem

∵ cos Ф = - 8/17

∵ Ф lies in the 3rd quadrant

- In the 3rd quadrant sin and cos are negative values, but tan is

 a positive value

∵ sin²Ф + cos²Ф = 1

∴ sin²Ф + (-8/17)² = 1

∴ sin²Ф + 64/289 = 1

- Subtract 64/289 from both sides

∴ sin²Ф = 225/289 ⇒ take √ for both sides

∴ sin Ф = ± 15/17

∵ Ф lies in the 3rd quadrant

∴ sin Ф = -15/17

∵ cos 2Ф = 2cos²Ф - 1 ⇒ the rule of the double angle

∵ cos Ф = - 8/17

∴ cos 2Ф = 2(-8/17)² - 1 = (128/289) - 1 = - 161/289

* cos 2Ф = - 161/289

∵ tan 2Ф = sin 2Ф/cos 2Ф

∵ sin 2Ф = 2 sin Ф × cos Ф

∵ sin Ф = - 15/17 and cos Ф = - 8/17

∴ sin 2Ф = 2 × (-15/17) × (-8/17) = 240/289

∵ cos 2Ф = - 161/289

∴ tan 2Ф = (240/289)/(-161/289) = - 240/161

* tan 2Ф = - 240/161

3 0
3 years ago
A sample was taken of the salaries of 20 employees from a large company. The following are the salaries (in thousands of dollars
seropon [69]

Answer:

21,500

Step-by-step explanation:

Given data ( in thousand ) in this year,

28 31 34 35 37 41 42 42 42 47 49 51 52 52 60 61 67 72 75 77,

If each data is increased by $ 3000 in the next year,

So, the data for the next year,

31 34 37 38 40 44 45 45 45 50 52 54 55 55 63 64 70 75 78 80,

Since, the data is already arranged in the ascending order,

The median is 51 which is between 50 and 52,

Thus, the lower half of the Data is, 31 34 37 38 40 44 45 45 45 50,

Having median Q_1=\frac{40+44}{2} = \frac{84}{2} = 42,

Upper half of the data is 52 54 55 55 63 64 70 75 78 80,

Having median Q_3=\frac{63+64}{2}=\frac{127}{2} = 63.5

Hence, the interquartile range = Q_3-Q_1

= 63.5 - 42

= 21.5

That is, the Interquartile range would be 21, 500.

7 0
3 years ago
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