The probability is 0.3, or 30%.
These are not independent events; one pill being chosen will affect the probability after that, as the pill will not be replaced before selecting the next one.
The probability of getting exactly 1 narcotic pill is given by:
(6/15)(9/14)(8/13) = 432/2730. It does not matter what order the narcotic pill is in, the overall product will be the same.
The probability of getting exactly 2 narcotic pills is given by:
(6/15)(5/14)(9/13) = 270/2730. Again, the order these are found in does not matter, as it is multiplication and will not change the product.
The probability of all 3 pills being narcotics is given by:
(6/15)(5/14)(4/13) = 120/2730.
Adding these three possibilities together, we have 822/2730 = 0.30.
y+z=10
x+z=8
x+y=12
(y+z)-(x+z)=10-8
y-x=2
y-x=2
y+x=12
solve simultaneously
x=5, y=7
then substitute to get z=3
hence xyz=573
Answer:
Antibodies.
Step-by-step explanation:
Hope this helped!
Answer:
probably a B.
Step-by-step explanation:
