Answer:
Dissolve 190 grams of silver nitrate in 250 mL of water.
Step-by-step explanation:
First, find the moles of AgNO₃ from the volume and concentration.
0.250 L × 4.5 mol/L = 1.125 mol
Next, find the mass of AgNO₃ using the molar mass.
1.125 mol × 170 g/mol = 191.25 g
Rounded to two significant figures, dissolve 190 grams of silver nitrate in 250 mL of water.
Vertical angles= two angels in the same potion different lines
No one is obtouse and one is acute
A + b = 45
a - b = 21
a = 21 + b
Use substitution
21 + b + b = 45
2b = 24
b = 12
45 - 12 = 33
The numbers are 33 and 12
Answer:
The equation of the line is y = 2x + 6
