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3 years ago

Derivative of cos(4x)

Mathematics

1 answer:

son4ous [18]3 years ago

7 0

D/dx ( cos (4x)) = - sin (4x) · d/dx ( 4x) = - 4 sin (4x)

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What is the area, in square inches, of the figure shown here?

andreev551 [17]

The area of the central rectangle = 5 * 3 = 15 ins^2

area of each triangle = 1/2*3*3 = 4.6 ins^2

Total area = 2*4.5 + 15 = 24 ins^2 (answer)

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3 years ago

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Need answer quick please answer quick

Natalka [10]

Answer : 1⅖ft.²

Given :-

Print is 7/8 ft wide and 1⅗ ft long .

To Find :-

The area of the print .

Here the length of the print is 1⅗ ft . So on converting this into improper fraction , we have ;

→ length = 1⅗ ft = (5*1+3)/5 ft = (5+3)/5ft = 8/5ft.

Also ,

→ breadth = 7/8ft .

We know that the area of a rectangle is ,

→ Area = length * breadth

On substituting the respective values,

→ Area = 8/5 ft. * 7/8ft

→ Area = 7/5 ft.²

After converting improper fraction into mixed fraction ,

→ Area = 1⅖ ft² .

Henceforth the area of the print is 1⅖ft.² .

I hope this helps.

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3 years ago

How many times smaller is 2 × 10-3 than 4 × 10-2? PLEASE HELP

NNADVOKAT [17]

<h2>The required "option A) 20" is correct.</h2>

Step-by-step explanation:

Let x be the smaller than 4 × $10^{-2}$ .

To find, the number of times smaller is 2 × $10^{-3}$ than 4 × $10^{-2}$ = ?

∴ x = $\dfrac{4\times 10^{-2}}{2\times 10^{-3}}$

= 2 × $10^{-2}$ × $10^{3}$

Using the identity,

$a^{m}=\dfrac{1}{a^{-m}}$

= 2 × $10^{-2+3}$

Using the identity,

$a^{m} \timesa^{n}=a^{m+n}$

= 2 × $10^{1}$

= 2 × 10

= 20

Thus, the required "option A) 20" is correct.

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3 years ago

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Oxana [17]

After figuring out a common difference in this pattern, we can get further terms in the pattern:
1, -2, 2, -4, 0, -3, -1

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3 years ago

How do you show your work for this problem?

laiz [17]

Answer:

i cant see it

Step-by-step explanation:

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