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sukhopar [10]
3 years ago
14

Find the transition matrix from B to B'. B = {(-1,2), (3, 4)), B' = {(1, 0), (0, 1)} STEP 1: Begin by forming the following matr

ix -1 2 0 [B":8] = 4 0 STEP 2: Determine the transition matrix. -2/5 3/10 1/10 Need Help? Read It Talk to a Tutor
Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:  The required matrix is

T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .

Step-by-step explanation:  We are given to find the transition matrix from the bases B to B' as given below :

B = {(-1,2), (3, 4)) and B' = {(1, 0), (0, 1)}.

Let us consider two real numbers a, b such that

(-1,2)=a(1,0)+b(0,1)\\\\\Rightarrow (-1,2)=(a,b)\\\\\Rightarrow a=-1,b=2.

Again, let us consider reals c and d such that

(3,4)=c(1,0)+d(0,1)\\\\\Rightarrow (3,4)=(c,d)\\\\\Rightarrow c=3,d=4.

Therefore, the transition matrix is given by

T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .

Thus, the required matrix is

T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .

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3 years ago
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Inverse of -5-9x/x-6

Step-by-step explanation:

Steps:

1: Interchange the variables x and y.      

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2: Solve x = 6y-5/y+9 for y

3: Multiply both sides by y+9

4: Simplify and Expand

5: Subtract 9x from both sides.

6: Simplify and Subtract y from both sides then Simplify again

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<em><u>Hope this helps.</u></em>

6 0
3 years ago
Read 2 more answers
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