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4 years ago

How many 350 mL cans of coke can be filled from a 20.3 L tank of coke?

Mathematics

1 answer:

erastova [34]4 years ago

5 0

Answer:

x = 58

Step-by-step explanation:

We know that,

1 mL = 0.001 L

So, 350 mL = 0.35 L

Let x cans of coke can be filled from a 20.3 L tank of coke. So,

Accoding to question,

$0.35\times x =20.3\\\\x=\dfrac{20.3}{0.35}\\\\x=58$

So, there are 58 350 mL cans of coke that can be filled from a 20.3 L tank of coke.

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What is the value of f(x) = 2 • 2^x for f(–2)? Will Give brainliest answer!!!

Sedbober [7]

For f(-2), x will equal -2.

Plug the x-value into the equation:

$2 \times 2^{-2}$

A negative exponent means that the term turns into a fraction, with 1 as the numerator and the positive exponent as the denominator.
Solve 2^(-2):

$2^{-2} = \frac{1}{2^{2}} = \frac{1}{4}$

Solve the problem:

$2 \times \frac{1}{4} = \frac{1}{2}$

f(-2) will equal 1/2.

5 0

3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$