If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Answer:
BF
BA
AG
Step-by-step explanation:
Answer:
134 Cookies
Step-by-step explanation:
you first multiply 8 with 16
then you add six to the product
Answer:
y=0.5x
Step-by-step explanation: Plot the points then draw the line to then use the slope formula y=mx+b m is slope which is 1/2 which is 0.5, you can use either, and b is the y-intercept which is (0,0)
Answer:
51ft^2
Step-by-step explanation:
Given data
Side of square patio= 9ft
Area= 9*9= 81 ft^2
New length = 9+3= 12ft
New Widht = 9+2= 11ft
New Area= 12*11
New Area= 132ft^2
Hence the area added is
=132-81
=51ft^2
