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drek231 [11]
3 years ago
10

If marissa left her apartment at 7:00am riding her bike at 12 mi/h. At 7:30 am her roommate set off after her riding her moped a

t 18 mi/h. How long did it take marissas roommate to find marissa
Mathematics
1 answer:
mamaluj [8]3 years ago
4 0

Answer:

The answer to your question is It will take 1 hour to find Marissa

Step-by-step explanation:

Data

Marissa    time = 7:00 am      speed = 12 mi/h

Roommate  time = 7:30 am   speed = 18 mi/h

Process

1.- Calculate the distance traveled by Marissa in 30 min (0.5 h)

    d = vt

    d = (12)(0.5)

    d = 6 mi

2.- Write an equation to solve this problem

Distance  traveled by Marissa = Distance traveled by the roommate

                                       6 + vmt = vrt

- Substitution

                                       6 + 12t = 18t

- Solve for t

                                       6 = 18t - 12t

                                        6 = 6t

                                        t = 6/6

                                        t = 1 h

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When do you can ride her bike .8 miles in six minutes how many miles can she ride her bike and 1.5 hours
Dafna11 [192]
They can ride their bike 12 miles because in 6 minutes they ride 0.8 miles so in 1.5 hours they ride 12 miles. 0.8 * 10 = 8 miles 1 hour so 0.8 * 5 = 4 miles 0.5 hours            8 miles + 4 miles =12 miles           1 hour + 0.5 hours = 1.5 hours
7 0
3 years ago
The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti
melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that m = 100, \mu = \frac{1}{100} = 0.01

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

P(X > x) = e^{-\mu x}

This is P(X > 190). So

P(X > 190) = e^{-0.01*190} = 0.1496

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

P(X > x) = 0.08

So

e^{-0.01x} = 0.08

\ln{e^{-0.01x}} = \ln{0.08}

-0.01x = \ln{0.08}

x = -\frac{\ln{0.08}}{0.01}

x = 252.6

Capacity of 252.6 cubic feet per second

5 0
3 years ago
Brainliestttt UsaTestPrep
lianna [129]

The answer to this question is:

36π cm³

your welcome.

Please brainliest

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Enrollment is the ski/snowboard club increase by 30 percent this year. there are now 182 students in this club how many students
lbvjy [14]
127 students were in the club last year
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Please answer this! I really suck at math and I need to do well.
Mariulka [41]

I believe it would be G.

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