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4 years ago

One number is 18 more than another number. The sum of the numbers is 36. find the numbers

1 answer:

7 0

We can use a system of equations in order to solve for both of the numbers. Let's start off by assigning variables to each number. The bigger number can be 'x', and the smaller number can be 'y'.

We can make two equations from the given:

x = 18 + y

("One number is 18 more than another number")

x + y = 36

("The sum of the numbers is 36")

If you look at the first equation, the variable 'x' already has a value (18 + y). We can input its value into the second equation in order to solve for y:

x + y = 36

(18 + y) + y = 36

18 + 2y = 36

2y = 18

y = 9

Input the value of 'y' into the first equation:

x = 18 + y

x = 18 + 9

x = 27

One number is 27 and the other number number is 9.

Let me know if you'd like me to explain anything I did here.

- breezyツ

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Julli [10]

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3 years ago

An investment of $900 earns 6% annual interest and is compounded semi-annually. Write an equation

nalin [4]

Answer:

$A=900(1+\frac{0.06}{2})^{2(t)}$

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 6% into a decimal:

6% -> $\frac{6}{100}$ -> 0.06

Since the interest is compounded semi-annually, we will use 2 for n. Lets plug in the values now and your equation will be:

$A=900(1+\frac{0.06}{2})^{2(t)}$

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2 years ago

If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se

notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 100, \sigma = 5$