/* package whatever; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
class NestedLoops {
public static void main (String [] args) {
int numRows = 4;
int numCols = 5;
int i,j;
char ch = 'A';
// Note: You'll need to declare more variables
/* Your solution goes here */
for ( i = 0; i < numRows; i++) { // Outer loop runs for numRows times
for ( j = 0; j < numCols; j++) { // Inner loop runs for numCols times
System.out.print(i+1);
System.out.print((char)(ch+j));
System.out.print(" ");
}
}
System.out.println("");
return;
}
}
The answer to this question is b that's the answer
Answer:
C. sqrt(Math)
Explanation:
All but one of options A to E are is not a static method.
Only option C is a static method. The sqrt() is a static method of Math, that can always be used as Math.sqrt() is used;
The Math class defines all of its methods to be static. Invoking Math methods is done by using Math as a method rather than a variable of type Math; this means that sqrt(Math) doesn't rely on instance variables and don't need to be overridden, unlike others.
Lastly, sqrt(Math) is a static method because unlike other options, it is an utility method, and it is relevant to computations on primitive data types.
The purpose of the static method is in large part to offer a standard library of functions, and it doesn't need to be applied directly to an object.
