Firstly let's find the dimension of this large rectangle:(given)
Area of Rectangle = 660 x 66 =43,560 ft²
And we know that 1 acre = 43,560 ft², then each rectangle has an area of 1 acre & the 20 acres will correspond to 20 x 43560 = 871,200 ft²
We know that the 20 acres form a rectangle. We need to know what is their disposition:
1) We would like to know the layout of the rectangles since we have 4 possibilities FOR THE LAYOUTS
Note that W=66 & L=666 = 43,956 ft²/ unit )
lay out shape could be either:(in ft)
1 W by 20 L (Final shape Linear 66 x 13320 = 879,120) or
2 W by 10 L (Final shape Stacked 132 x 6660 = 879,120) or
4 W by 5 L (Final shape Stacked 264 x 3330 = 879,120) or
2) We would like to know the number of participants so that to allocate equal space as well as the pedestrian lane, if possible, if not we will calculated the reserved space allocated for pedestrian/visitors)
3) Depending on the shape given we will calculate the visitor space & we will deduct it from the total space to distribute the remaining among the exhibitors.
4) (SUGGESTION) Assuming it's linear, we will reserve
20ft x 13320 ft = = 266,400 ft² and the remaining 612,720 ft² for exhibitors
5) Depending on the kind of the exhibition, we will divide the 612,720 ft² accordingly
6) How can we select the space allocated for each exhibitor:
the 617,720 ft² could be written as a product of prime factors:
612720 = 2⁴ x 3² x 5 x 23 x 37
If you chose each space will be185 ft² , then we can accommodate up to 3,312 exhibitors.
Obviously you can choose any multiple of the prime factors to specify the area allocated & to calculate the number of exhibitors accordingly
Answer:
Step-by-step explanation:
como pongo el brainly en español?
Recall the following identities:
from which we get
Since
is in the fourth quadrant
we know that
should be positive, so when we take the square root here, we should take the positive root.
Now recall that
and since
is in the fourth quadrant, we expect
to be negative. So,
One final identity:
from which we get
Answer:
The remaining credit after 45 minutes of calls is $18.70
Step-by-step explanation:
Here, we have a linear model to work with
Let us have the coordinates as follows;
(time calling time, credit remaining)
So we have two points as follows;
(24,21.64) and (35,20.10)
The slope will be;
(20.1-21.64)/(35-24) = -1.54/11 = -0.14
So the equation looks like;
y = -0.14x + c
To get the y-intercept, we simply substitute a point
Let us use (35,20.10)
20.10 = -0.14(35) + c
c = 20.10 + 4.9
c = 25
So the full equation is;
y = -0.14x + 25
So for 45 minutes, simply substitute 45 for x
We have this as:
y = -0.14(45) + 25
y = -6.3 + 25 = $18.70
(30.65)
it takes an object the ground times the constant gravity. in this case 2.5 seconds times 9.807 meter per square second will then give us the 30.65 meter.
have a nice day!