Answer:
B. (-5/13, 12/13)
Step-by-step explanation:
The point at distance x from π in the clockwise direction is the reflection of point T across the y-axis. Hence the coordinates are the same, except that the sign of the x-coordinate is reversed.
The point of interest is (-5/13, 12/13).
Using the equations for tangent and secant lines:
Let the unknown length of the line inside the circle = y
6^2 = 3 x (y+3)
Simplify:
36 = 3y+9
Subtract 9 from both sides:
27 =3y
Divide both sides by 3:
Y = 9
Now add to get x:
X = 9 + 3 = 12
X = 12
First, find the vertices of the shaded region. You can do this my graphing or by solving a system of equations for each pair of functions. <em>I am going to find them by graphing.</em>
x ≥ 0 and y ≥ 0 place the shaded region in the first quadrant with a vertex at (0, 0)
now graph y ≤ 3. a vertex is at (0, 3)
now graph y < -2x + 5. a vertex is at (1, 3). the other vertex is the x-intercept (when y = 0).
0 = -2x + 5
-5 = -2x
So, the vertex is 
Next, input the coordinates of the vertices into the objective function.
C = -6x + 5y
(0, 0): C = -6(0) + 5(0)
= 0 + 0
= 0
(0, 3): C = -6(0) + 5(3)
= 0 + 15
= 15
(1, 3): C = -6(1) + 5(3)
= -6 + 15
= 9
: C = -6(\frac{5}{2}[/tex]) + 5(2)
= -15 + 10
= -5
The maximum is C = 15 which occurs at vertex (0, 3)
Answer: A
Hi the answer is x^5.
19 is a prime number, so 3 cannot be a factor. However, bother terms contain x^5, this is the greatest common factor.