Well,you have the answer on your paper already...
<span> f(x)=4x^8+7x^7+1x^6+
</span>∴<span> f(-2)=4(-2)^8+7(-2)^7+1(-2)^6+1
</span>∴ <span>f(-2)=(4x256) + (7x-128) + (1x64) +1
</span>∴ <span>f(-2)=1024 - 896 + 64 +1
</span>∴ <span>f(-2)= 193</span>
Simply simplify:
7a³(7a²)-4a^6 ⇒ 49a^6 - 4a^6 ⇒ 45a^6
Hope that helps!
2x^2-4x+2=x+2. 2x^2-4x+2-x-2=0. 2x^2<span>-3x-0=0. use quadratic formula = </span>(-b+- squareroot(b^2-4ac))/2a. so ur a=2<span> b=-3 c=0. hope this helped</span>
