For what value of x is sin x = cos 19º, where 0°< x < 90°
1 answer:
Check the picture below, that one in the picture is just an example of the correspondence of sine and cosine in a right-triangle, in this case, we're in the 0° < x < 90°, so in the I Quadrant, and thus we have a right-triangle.
to make it short, sin(90° - 19°) = cos(19°), or that is sin(71°), thus x = 71.
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What is a normal distribution?
A normal distribution is a function on some random variables, which represent the set of all those random variables in a symmetrical bell shape about the mean value.
It shows that the probability of occurrence of some data which is distributed over a function is more at or around the mean.
It is also known as probability distribution curve.
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What is the shape of the normal distribution?
The normal distribution curve is at it's peak at the mean value. This shows that the probability of occurrence of the data or value is more concentrated or distributed about the mean. It is also symmetric about the mean. As we more further from the mean, we see that the normal distribution curve gradually decreases showing that the probability of occurrence of the data or the values decreases. The shape that this curve forms is like a bell-shaped. So the shape of normal distribution is bell shape.
Hence, the shape of the normal distribution is bell shape and it is also symmetrical from the left and right sides about the origins (mean).
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The volume of the rectangular prism is
Where:
B is the base area
H is the height
Since the base area is 160 feet^2
Since the volume is 1360 feet^3
Substitute them in the rule above
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