Divide each term by U and simplify. X=y/U and W=2/U. Next, solve the equation for y. Simplify the left side then cancel the common factor of U. 1/1*y/1=y
W=2/U. Multiply 1/1*y/1=y/1 so, y/1=y and W=2/U. Next, divide y/y to get 1 now y=y, still W=2/U. Now, move all terms containing y to the left side. Since, Y contains the variable to solve for, move it to the left side of the equation by subtracting y from both sides. Now, y-y=0 still W=2/U. Next, subtract y from y to get zero and still W=2/U. Subtract y from y to get zero or 0=0 and W=2/U is your expression since 0=0.
Next: UW=m and WX=y+14 write expression for UX
First, divide each term by W and simplify. U=m/W, WX=y+14. Next, solve the equation for Y. Move y from the right side of the equation to the left side. Still, U=m/W and y=-14+WX. We must reorder -14 and WX. U=m/w and y=WX-14.
Replace the variable U with m/W in the expression to (m/W)X. Next, simplify (m/W)X. Now, write X and a fraction with denominator 1. Looks like this
fractions are side by side m/W X/1 . Multiply, m/W and X/1 to get mX/W.
mX/W is your final expression for UW=m and WX=y+14 expression for UX.
6sqrt2 for both since there equivalent
Step-by-step explanation:
-1×5 1×3
------ -----
3×5 -5×3
=
-5/15 -3/15
-5/15×4/4 ;
-3/15×4/4
=
-20/60 ;
-12/60
you can write any 8 rational no. between them
please mark as brainliest answer as it will also give you 3 pts
Answer:
9 ft
Step-by-step explanation:
Let's begin with the formula for the volume of a square pyramid. If s is the base length, then the area of the base is s^2. The volume of the pyramid is then V = (1/3)(base area)(height). We know the volume and the base length (s), and want to find the height. Solving V = (1/3)(base area)(height)
for height, we get:
3V = (base area)(height), or
3V
---------------- = height
base area
Substituting 75 ft^3 for V and (5 ft)^2 for base area, we get:
3(75 ft^3) 9 ft
height = ------------------ = ----------------- = 9 ft
25 ft^2 1
The picture below has both of the answers to your problem.
