Answer:
∠ C = ∠BCD = 30°
Step-by-step explanation:
∠ EDF = ∠GFC = 110° [ corresponding angles ]
Now consider triangle BCF
∠FBC + ∠ABC = 180° [ straight line angle ]
∠FBC + 100° = 180°
∠FBC = 180 - 100 = 80°
∠BFC + ∠GFC = 180° [ straight line angle ]
∠BFC + 110° = 180°
∠BFC = 180 - 110 = 70°
Sum of angles of triangle is 180°
Therefore , in triangle BCF
That is ,
∠F + ∠B + ∠ C = 180°
70° + 80° + ∠C = 180°
∠C = 180 - 150 = 30°
Answer: The length of the path = 157 inches { approx}
Step-by-step explanation:
Given: The length of the path = 4 meters
1 meter = 100 centimeters
So 4 meters = 400 centimeters
Also 1 in. ≈ 2.54 cm

Now, 
![=157.480314961\approx 157 \ \ \ \ \ \text{ [Rounded to the nearest inch.]}](https://tex.z-dn.net/?f=%3D157.480314961%5Capprox%20157%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5Ctext%7B%20%5BRounded%20to%20the%20nearest%20inch.%5D%7D)
Hence, the length of the path = 157 inches { approx}
L = -4,4
E = -2, -3
N = 2,1
I = 4,3
E = 1,3
Answer:
yes they are similar
Step-by-step explanation: