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skad [1K]
3 years ago
13

What is a triangle inscribed in a semicircle called

Mathematics
1 answer:
Tanya [424]3 years ago
5 0
Right traingle

I hope it helped you!
You might be interested in
Please help me please<br><br>​
kenny6666 [7]

Answer:

first was the tan4cot

second was (-g,f)

4 0
3 years ago
Nine new employees, two of whom are married to each other, are to be assigned nine desks that are lined up in a row. If the assi
meriva

Answer:

The probability is 0.8

Step-by-step explanation:

The key to answering this question is considering the fact that the two married employees be treated as a single unit.

Now what this means is that we would be having 8 desks to assign.

Mathematically, the number of ways to assign 8 desks to 8 employees is equal to 8!

Now, the number of ways the couple can interchange their desks is just 2 ways

Thus, the number of ways to assign desks such that the couple has adjacent desks is 2(8!)

The number of ways to assign desks among all six employees randomly is 9!

Thus, the probability that the couple will have adjacent desks would be ;

2(8!)/9! = 2/9

This means that the probability that the couple have non adjacent desks is 1-2/9 = 7/9 = 0.77778

Which is 0.8 to the nearest tenth of a percent

4 0
3 years ago
The graph shows Ms. Padilla's monthly cell phone cost, where x is the number of minutes she uses the phone during the month.
balu736 [363]

Answer: the X intercept mean this here

Ms.

Padilla is charged $0.04/min.

Ms. Padilla pays $16 for months she makes 0 min of calls

Step-by-step explanation:

7 0
1 year ago
Can somebody answer questions i) and j) please
frutty [35]

i)

Pythagorean's theorem: √50

j)

Pythagorean's theorem: √1/2

8 0
3 years ago
Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic
Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

df = n-1= 10-1=9

d.9

b) s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15

a.15

c) For this case we have the sample size n = 25 and the sample variance is s^2 =400 , the standard error can founded with this formula:

SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

df = n-1= 10-1=9

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

SS = \sum_{i=1}^n (X_i -\bar X)^2

And the sample variance for this case can be calculated from this formula:

s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is s^2 =400 , the standard error can founded with this formula:

SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80

8 0
3 years ago
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