Answer:
1. f(x) = -2x^2-12x-19
2. f(x)= 2x^2+12x+17
3. f(x)= -2x^2+12x-17
4. f(x)= 2x^2-12x+17
Step-by-step explanation:
Just took the same test. :)
You could multiply again by 2 or long multiply by 2
Answer:
31
Step-by-step explanation:
100-7= 93
93÷3=31
Answer:
No extraneous solution
Step-by-step explanation:
We have the logarithmic equation given by,
![\log_{2}[\log_{2}(\sqrt{4x})]=1](https://tex.z-dn.net/?f=%5Clog_%7B2%7D%5B%5Clog_%7B2%7D%28%5Csqrt%7B4x%7D%29%5D%3D1)
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
i.e. 
So, the solution of the given equation is x=4.
Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is
.
Therefore, the domain of the given function is x > 0.
We know that the extraneous solution is the solution which does not belong to the domain.
But as x=4 belongs to the domain x > 0.
Thus, x = 4 is not an extraneous solution.
Hence, this equation does not have any extraneous solution.
Dividing by 2 is obvious. Square root is "a number which produces a specified quantity when multiplied by itself." Essentially the opposite of exponents.