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andrew-mc [135]
3 years ago
11

It takes Javier 12 more minutes to get to work than it takes Michaela. It takes Javier 40 minutes to get to work. How long does

it take Michaela?
Mathematics
1 answer:
lapo4ka [179]3 years ago
3 0

Answer:

342624

Step-by-step explanation:

4236terrg

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Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw
PolarNik [594]

Answer:

Using <u>backward reasoning</u> we want to show that <em>"We can never get nine 0's"</em>.

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

<u>There were 9 </u><u>0's</u><u>:</u>

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

<u>There were 9 </u><u>1's</u><u>:</u>

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

<u />

5 0
3 years ago
Four times a number decreased by 6 is less than -2
Whitepunk [10]

Answer:

-5.5

Step-by-step explanation:

well lets make an equation first. 4x-6<-2 . Now we have to find what x equals.

And now we know that x<1

5 0
3 years ago
Which is the best approximation for the solution of the system of equations
miv72 [106K]
X = 0.882
y = 0.647
seems to be a good approximation of the solution.

3 0
3 years ago
Read 2 more answers
a delivery truck is carrying and 8713 lb load of pet food. At a weighing station, the loaded truck weighs 17200 lb. What is the
netineya [11]

We know that the load is 8713 lbs.

The total weight (truck + load) is 17200 lb.

Then, we can calculate the weight of the empty truck as:

\begin{gathered} L=8713 \\ W=L+T=17200 \\ \Rightarrow T=W-L \\ T=17200-L=17200-8713=8487 \\  \end{gathered}

Answer: the empty truck's weight is 8487 lb.

T: empty truck's weight

W: total weight (loaded truck's weight)

L: Load

The equation is:

T = W - L

6 0
1 year ago
(I'm so lost I need help with this question!!!)
lozanna [386]

Answer:

1. 5 cm

2. 7.07 cm

Step-by-step explanation:

According to your provided information, the area of a square is A = s^2. They also tell you that the area of the square in the picture is 25cm^2. That means that, to find the length of any side (s), you just need to plug 25 in as the area. So

25 = s^2 ... Take the square root of both sides to isolate s.

s = ±5 ... But since we're talking about length, we only take the value positive five. (Length can't be a negative value.)

Now we have the length of any side as 5 cm, and they want us to find the length of the diagonal. We can use the Pythagorean theorem, a^2 + b^2 = c^2, where c will be the diagonal we want. We can do this because we know that ANY side of this square is s = 5, so if we plug that into a^2 + b^2 = c^2, we get

5^2 + 5^2 = c^2 ... 5 times 5 is 25

25 + 25 = c^2 ... Add

50 = c^2 ... Take the square root of both sides

c = √50 ... Use a calculator

c ≈ 7.07

8 0
3 years ago
Read 2 more answers
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