Answer:
f'(x) = 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
Step-by-step explanation:
f' of tan(x) = sec²(x)
f' of csc(x) = -csc(x)cot(x)
General Power Rule: uⁿ = xuⁿ⁻¹ · u'
Step 1: Write equation
2tan³(x) + 5csc⁴(x)
Step 2: Rewrite
2(tan(x))³ + 5(csc(x))⁴
Step 3: Find derivative
d/dx 2(tan(x))³ + 5(csc(x))⁴
- General Power Rule: 2 · 3(tan(x))² · sec²(x) + 5 · 4(csc(x))³ · -csc(x)cot(x)
- Multiply: 6(tan(x))²sec²(x) - 20(csc(x))³csc(x)cot(x)
- Simplify: 6tan²(x)sec²(x) - 20csc⁴(x)cot(x)
- Factor: 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
Answer:

Step-by-step explanation:
The formula to find the volume of a triangular prism is

From the diagram we are given we can see that

Therefore the volume of the triangular prism is

Answer:
The average rate of change is equal to
Step-by-step explanation:
we have
-----> this is a linear direct variation
we know that
The rate of change of a linear variation is a constant
The rate of change of a linear variation is equal to the slope of the line
In this problem the slope of the line is equal to
therefore
The average rate of change is equal to
<u>Verify</u>
the average rate of change is equal to

In this problem we have


Substitute

Answer:
-1.75
Step-by-step explanation:
This should be it, but you didn't provide options although you put "Which of the following.."