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2 years ago

32 lb 12 ounces equals in pounds

Mathematics

1 answer:

Radda [10]2 years ago

4 0

Answer:

32 3/4 lb

Step-by-step explanation:

32 lb 12 oz = ? lb

Rewrite 12 oz as (12/16) lb.

Then:

32 lb 12 oz = 32 lb + (3/4) lb, or 32 3/4 lb

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What is the answer to 8k-4(k-1)+7-k

seropon [69]

8k-4k+4+7-k =
8k-4k-k+4+7 =
3k+11

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Pleas help !!!! Need explanation as well

Fynjy0 [20]

Answer:

B, they are independent events separate from each other.

Step-by-step explanation:

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Can someone help me with this, please? No links or false answers, please

VARVARA [1.3K]

The exact value is found by making use of order of operations. The

functions can be resolved using the characteristics of quadratic functions.

Correct responses:

$\displaystyle 1\frac{4}{7} \div \frac{2}{3} - 1\frac{5}{7} =\frac{9}{14}$

x = -4, y = 12

When P = 1, V = 6

$\displaystyle x = -3 \ or \ x = \frac{1}{2}$

$\displaystyle i. \hspace{0.1 cm} \underline{ f(x) = 2 \cdot \left(x - 1.25 \right)^2 + 4.875 }$

ii. The function has a minimum point

iii. The value of x at the minimum point, is 1.25

iv. The equation of the axis of symmetry is x = 1.25

<h3>Methods by which the above responses are found</h3>

First part:

The given expression, $\displaystyle \mathbf{ 1\frac{4}{7} \div \frac{2}{3} -1\frac{5}{7}}$ , can be simplified using the algorithm for arithmetic operations as follows;

$\displaystyle 1\frac{4}{7} \div \frac{2}{3} - 1\frac{5}{7} = \frac{11}{7} \div \frac{2}{3} - \frac{12}{7} = \frac{11}{7} \times \frac{3}{2} - \frac{12}{7} = \frac{33 - 24}{14} =\underline{\frac{9}{14}}$

Second part:

y = 8 - x

2·x² + x·y = -16

Therefore;

2·x² + x·(8 - x) = -16

2·x² + 8·x - x² + 16 = 0

x² + 8·x + 16 = 0

(x + 4)·(x + 4) = 0

x = -4

y = 8 - (-4) = 12

y = 12

Third part:

(i) P varies inversely as the square of V

Therefore;

$\displaystyle P \propto \mathbf{\frac{1}{V^2}}$

$\displaystyle P = \frac{K}{V^2}$

V = 3, when P = 4

Therefore;

$\displaystyle 4 = \frac{K}{3^2}$

K = 3² × 4 = 36

$\displaystyle V = \sqrt{\frac{K}{P}$

When P = 1, we have;

$\displaystyle V =\sqrt{ \frac{36}{1} } = 6$

When P = 1, V = 6

Fourth Part:

Required:

Solving for x in the equation; 2·x² + 5·x - 3 = 0

Solution:

The equation can be simplified by rewriting the equation as follows;

2·x² + 5·x - 3 = 2·x² + 6·x - x - 3 = 0

2·x·(x + 3) - (x + 3) = 0

(x + 3)·(2·x - 1) = 0

$\displaystyle \underline{x = -3 \ or\ x = \frac{1}{2}}$

Fifth part:

The given function is; f(x) = 2·x² - 5·x + 8

i. Required; To write the function in the form a·(x + b)² + c

The vertex form of a quadratic equation is f(x) = a·(x - h)² + k, which is similar to the required form

Where;

(h, k) = The coordinate of the vertex

Therefore, the coordinates of the vertex of the quadratic equation is (b, c)

The x-coordinate of the vertex of a quadratic equation f(x) = a·x² + b·x + c, is given as follows;

$\displaystyle h = \mathbf{ \frac{-b}{2 \cdot a}}$

Therefore, for the given equation, we have;

$\displaystyle h = \frac{-(-5)}{2 \times 2} = \mathbf{ \frac{5}{4}} = 1.25$

Therefore, at the vertex, we have;

$k = \displaystyle f\left(1.25\right) = 2 \times \left(1.25\right)^2 - 5 \times 1.25 + 8 = \frac{39}{8} = 4.875$

a = The leading coefficient = 2

b = -h

c = k

Which gives;

$\displaystyle f(x) \ in \ the \ form \ a \cdot (x + b)^2 + c \ is \ f(x) = 2 \cdot \left(x + \left(-1.25 \right) \right)^2 +4.875$

Therefore;

$\displaystyle \underline{ f(x) = 2 \cdot \left(x -1.25\right)^2 + 4.875}$

ii. The coefficient of the quadratic function is 2 which is positive, therefore;

The function has a minimum point.

iii. The value of x for which the minimum value occurs is -b = h which is therefore;

The x-coordinate of the vertex = h = -b = 1.25

iv. The axis of symmetry is the vertical line that passes through the vertex.

Therefore;

The axis of symmetry is the line x = 1.25.

Learn more about quadratic functions here:

brainly.com/question/11631534

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2 years ago

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Write a system of equations with the solution (4,-3)

Slav-nsk [51]

Answer:

y = 3x-15 and y = x-7

Step-by-step explanation:

We are asked to write a system of equations with the solution (4,-3)

It is sufficient if we find two lines passing through this point.

Let us take first line as with slope 3.

Then the equation would be of the form

y-y1 = m(x-x1)

y+3 = 3(x-4)

Or y = 3x-15 is one line

Let second line have slope 1

y+3 = 1(x-4)

y = x-7

Now we have two systems of equations as

y = 3x-15 and y = x-7

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3 years ago

A rocket is launched from the top of a 55-foot cliff with an initial velocity of 138 ft/s.

melisa1 [442]

For this case we have that the equation that describes the height is:

$h = -16t ^ 2 + vt + c$

Where,

v: initial speed

c: initial height

Substituting values we have:

$h = -16t ^ 2 + 138t + 55$

Then, to find the time, we use the quadratic formula:

$t =\frac{-b +/-\sqrt{b^2 - 4ac} }{2a}$

Substituting values we have:

$t =\frac{-138 +/-\sqrt{138^2 - 4(-16)(55)} }{2(-16)}$

Rewriting:

$t =\frac{-138 +/-\sqrt{19044 + 3520} }{-32}$

$t =\frac{-138 +/-\sqrt{22564}}{-32}$

$t =\frac{-138 +/-150.21}{-32}$

We discard the negative root because we want to find the time.

We have then:

$t =\frac{-138 -150.21}{-32}$

$t =\frac{-288.21}{-32} \\t=9$

Answer:

D. $0 = -16t^2 + 138t + 55; 9 s$

3 0

2 years ago