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Firlakuza [10]
2 years ago
6

Pls help within like 5 min. will give you anything!

Mathematics
2 answers:
Maru [420]2 years ago
6 0
The one you have marked is the correct one!
avanturin [10]2 years ago
3 0

i think the one you have selected is correct

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which property is illustrated by the equation below (r+s)+t=r+(s+t). A)Associative B)Commutative C)Distributive D)Identity
Lera25 [3.4K]
The associative property of addition is being demonstrated here. The parenthesis are moved around to "associate" or "group" the values into two different pairs.

Note: the associative property of multiplication is very similar and it is
a*(b*c) = (a*b)*c<span />
4 0
3 years ago
PLEASE HELP QUICKLY: (FIRST ANSWER GETS BRAINLIEST)
kodGreya [7K]

Answer:

Buy the batteries and stereo online:  

4.99*2= $9.98 +$90 = $99.98  

6.99-5.00 = $1.99  

99.98+1.99=$101.97  

3Cds in store  

7.97*3= $23.85  

5% tax = 1.19  

10% off = 2.39  

$23.85 - $1.19= $22.66  

22.66 + 101.97= $124.63  

All in store:  

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All online:  

9.98 + 90 + 26.85= 126.85 +$1.99 = 128.84

<u><em>(CREDIT: Hussain514)</em></u>

8 0
3 years ago
Trey made pasta in the shape of a square. He draws two lines to cut the pasta into smaller pieces. Which have 12 sides and 12 ve
Aleks [24]
12*12 =24........................
7 0
3 years ago
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triangle has sides measuring 2 inches and 7 inches If x represents the length in inches of the third side which inequality gives
il63 [147K]
We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (<span>Triangle Inequality Theorem)
so
inequality 1
</span>(2+7) \ \textgreater \  x \\  9 \ \textgreater \  x \\  x \ \textless \  9 in
<span>
inequality 2
</span>(x+2) \ \textgreater \  7 \\  x \ \textgreater \  7-2 \\  x \ \textgreater \  5 in
<span>
the answer is
</span>5 in  \ \textless \ x \ \textless \ 9 in<span>
</span>
6 0
3 years ago
7f^2 + Fz= ????????????????????!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
netineya [11]

Answer:

7f/z

Step-by-step explanation:

mat h wAyz

6 0
3 years ago
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