Pls help within like 5 min. will give you anything!

Kenneth signed up to receive Internet service for $13 per month plus a $30 start-up fee. Which equation could be used to find th

zimovet [89]

The equation 13x+30=134 can be used to find the number of months Kenneth can receive internet service.

Step-by-step explanation:

Given,

Start up fee to receive internet = $30

Per month charges = $13

Total amount = $134

Let,

x be the number of months.

y be the total cost.

y = 13x+30

Putting y=134

$134=13x+30\\13x+30=134$

The equation 13x+30=134 can be used to find the number of months Kenneth can receive internet service.

Keywords: equation, addition

Learn more about addition at:

#LearnwithBrainly

7 0

3 years ago

The vertex of this parabola is at (-5, -2). When the x-value is -4, the

dusya [7]

I am pretty sure that it's
A. 1

3 0

4 years ago

Read 2 more answers

Question 10 (multiple answer)

murzikaleks [220]

Answer:

The answerers are 90"; 45. 45 and 60, 60, 60.

Step-by-step explanation:

The two sides have the same length this would mean that they have the same angle measure on a triangle the only two answers with two of the same angle measures are 90"; 45. 45 and 60, 60, 60 so therefore they are your answers.

8 0

3 years ago

A family buys a studio apartment for $240,000. They pay a down payment of $60,000.

stealth61 [152]

Answer:

Part A: 25%
Part B: 40%

Step-by-step explanation:

Given the following questions:

$240000 for a studio apartment
$60000 as a down payment.

In order to find the answer, we use the formula to calculate the percentage for the total cost of the studio apartment and the down payment.

<u>Part A:</u>
$\frac{c\times n}{100}$
$\frac{25\times240000}{100} =25\times240000=60000$
$=60000$

<u>Part B:</u>
$\frac{c\times n}{100}$
$\frac{40\times240000}{100} =40\times240000=9600000\div100=96000$
$=96000$

The percent of a down payment of $60,000 for a $240,000 studio apartment is "25%." While the percent of a $96,000 dollar down payment for a $240,000 studio apartment is "40%."

Hope this helps.

8 0

3 years ago

Let V denote the set of ordered triples (x, y, z) and define addition in V as in

icang [17]

Answer:

a) No

b) No

c) No

d) No

Step-by-step explanation:

Remember, a set V wit the operations addition and scalar product is a vector space if the following conditions are valid for all u, v, w∈V and for all scalars c and d:

1. u+v∈V

2. u+v=v+u

3. (u+v)+w=u+(v+w).

4. Exist 0∈V such that u+0=u

5. For each u∈V exist −u∈V such that u+(−u)=0.

6. if c is an escalar and u∈V, then cu∈V

7. c(u+v)=cu+cv

8. (c+d)u=cu+du

9. c(du)=(cd)u

10. 1u=u

let's check each of the properties for the respective operations:

Let $u=(u_1,u_2,u_3), v=(v_1,v_2,v_3)$

Observe that

1. u+v∈V

2. u+v=v+u, because the adittion of reals is conmutative

3. (u+v)+w=u+(v+w). because the adittion of reals is associative

4. $(u_1,u_2,u_3)+(0,0,0)=(u_1+0,u_2+0,u_3+0)=(u_1,u_2,u_3)$

5. $(u_1,u_2,u_3)+(-u_1,-u_2,-u_3)=(0,0,0)$

then regardless of the escalar product, the first five properties are met for a), b), c) and d). Now let's verify that properties 6-10 are met.

a)

6. $c(u_1,u_2,u_3)=(cu_1,u_2,cu_3)\in V$

7.

$c(u+v)=c(u_1+v_1,u_2+v_2,u_3+v_3)=(c(u_1+v_1),u_2+v_2,c(u_3+v_3))\\=(cu_1+cv_1,u_2+v_2,cu_3+cv_3)=c(u_1,u_2,u_3)+c(v_1,v_2,v_3)=cu+cv$

8.

$(c+d)u=(c+d)(u_1,u_2,u_3)=((c+d)u_1,u_2,(c+d)u_3)=\\=(cu_1+du_1,u_2,cu_3+du_3)\neq (cu_1+du_1,2u_2,cu_3+du_3)=cu+du$

Since 8 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product $a(x,y,z)=(ax,y,az)$

b) 6. $c(u_1,u_2,u_3)=(cu_1,0,cu_3)\in V$

7.

$c(u+v)=c(u_1+v_1,u_2+v_2,u_3+v_3)=(c(u_1+v_1),0,c(u_3+v_3))\\=(cu_1+cv_1,0,cu_3+cv_3)=c(u_1,u_2,u_3)+c(v_1,v_2,v_3)=cu+cv$

8.

$(c+d)u=(c+d)(u_1,u_2,u_3)=((c+d)u_1,0,(c+d)u_3)=\\=(cu_1+du_1,0,cu_3+du_3)=(cu_1,0,cu_3)+(du_1,0,du_3) =cu+du$

9.

$c(du)=c(d(u_,u_2,u_3))=c(du_1,0,du_3)=(cdu_1,0,cdu_3)=(cd)u$

10

$1u=1(u_1,u_2,u3)=(1u_1,0,1u_3)=(u_1,0,u_3)\neq(u_1,u_2,u_3)$

Since 10 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product $a(x,y,z)=(ax,0,az)$

c) Observe that $1u=1(u_1,u_2,u3)=(0,0,0)\neq(u_1,u_2,u_3)$

Since 10 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product $a(x,y,z)=(0,0,0)$ .

d) Observe that $1u=1(u_1,u_2,u3)=(2*1u_1,2*1u_2,2*1u_3)=(2u_1,2u_2,2u_3)\neq(u_1,u_2,u_3)=u$

Since 10 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product $a(x,y,z)=(2ax,2ay,2az)$ .

8 0

3 years ago