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3 years ago

Hi there! Sorry to bother you, but can someone help me out with this?

Mathematics

2 answers:

MrRa [10]3 years ago

7 0

Answer:

1. Theorem; If you need to prove any type of triangle, you will need to get a specific theorem (such as SAS or ASA).

2. Proof; a proof connects with finding how two triangles are congruent or similar. They will be in a list in corresponding order, or it will not be correct.

Hope this helps!

tatiyna3 years ago

6 0

Answer: 1. C , 2. D

Step-by-step explanation:

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10^2+12^2+14^2+......+26^2=??

Kazeer [188]

Answer:

3156

Step-by-step explanation:

<em>Used formula:</em>
<em>(1² + 2² + 3² + ... + n²) =1/6*n(n + 1)(2n + 1)</em>

--------

10²+12²+14²+......+26² =
(2*5)²+(2*6)² + (2*7)² + ... + (2*13)² =
4*(5²+6²+7²+...+13²) =
4*(1²+2²+...+13² - (1²+2²+3²+4²)) =
4*(1/6*13(13+1)(2*13+1) - (1+4+9+16)) =
4*(1/6*13*14*27- 30) =
4*(819 - 30) =
4*789 =
3156

3 0

4 years ago

What is the formula for a trapezium

aleksklad [387]

A= (a+b/2) × h

Is the formula for a trapezoid

4 0

3 years ago

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago

34.607 to the nearest whole number

Elena L [17]

I know the answer is 35

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3 years ago

For every 15 Cheetos I ate 300 calories what's the unit rate

gregori [183]

Answer:

20 calories per Cheetos

Step-by-step explanation:

hope it helped

5 0

3 years ago