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r-ruslan [8.4K]
3 years ago
10

Use trig ratios to find the measure of the angle in this triangle. A .cos^-1(4/5) B. tan(4/5) tan^-1(4/5) C. sin(4/5) D. cos(4/5

) E. sin^-1(4/5)

Mathematics
1 answer:
ololo11 [35]3 years ago
8 0

Answer:

The answer is A

Step-by-step explanation:

Step 1: Use Cosine to find ∅

Cos∅=\frac{4}{5}

∅=Cos^{-1}(\frac{4}{5})

Therefore the answer is A

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On saturday, a minor league baseball team gave away baseball cards to each person entering the stadium. one group received 28 ba
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If you can drive 340 miles in 5 hours, what is the unit rate? *<br> (2 Points)<br> Enter your answer
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26 out of the 65 magazines at the bookstore are women's magazines. What percentage of the magazines at the bookstore are women's
egoroff_w [7]

The fraction \frac{26}{64} represents the number of women's magazines out of all the other magazines at the book store.

To find what percent of the magazines are women's magazines, we can turn \frac{26}{64} into a percent.

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3 years ago
The data set below shows the number of players on each softball team in a tournament:
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An outlier number is the number that's completely different from the rest.
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7 0
3 years ago
A quadratic equation is shown below:
sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

3x^{2}-11x+10=0 has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

\frac{d}{dx}(3x^{2}-11x+10)=6x-11

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}

6 0
3 years ago
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