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miss Akunina [59]
2 years ago
13

Steps are very much required they should be clear and neat please i need to understand this I'm taking a practice test for my fu

ture sats
ill report in inappropriate answers

Mathematics
1 answer:
Volgvan2 years ago
8 0

Answer:

2nd option

Step-by-step explanation:

the mean is calculated as

mean = \frac{sum}{count}

         = \frac{4x+5+7x-6-8x+2}{3}

         = \frac{3x+1}{3}

         = \frac{3x}{3} + \frac{1}{3}

        = x + \frac{1}{3}

You might be interested in
Please help me whit this (if you answer pls show the work)
adell [148]

Answer:

24 ft

Step-by-step explanation:

Use proportions! The old tent has sides of 10ft, and a base of 15ft. The new tent has sides of 16ft and a base of ____ ft.

So, 10/15 = 16/___. Cross multiple and you get 24ft!

8 0
3 years ago
Please help due in 3 min
andrezito [222]

Answer:

(h*h)(10) is the same as h(10)*h(10). Let's find the value of h(10) first. To do this, replace every x with 10 like so

Step-by-step explanation:

h(x) = 6-x

h(10) = 6-10

h(10) = -4

So,

h(10)*h(10) = (-4)*(-4)

h(10)*h(10) = 16

The final answer is 16

3 0
3 years ago
Read 2 more answers
2000 people are selected randomly from a certain population and it is found that 389 people in the sample are over 6 feet tall.
Airida [17]

Answer: 0.195

Step-by-step explanation:

given data:

population = 2000 people.

people Who are over 6 feet tall = 389.

Solution:

the point estimate of people over 6feet tall

= no of people over 6 feet tall / total population size

= 389/2000

= 0.195

the point estimate of people over 6 feet tall is 0.195

8 0
3 years ago
Thomas needs to buy a cardboard sheet that will allow him to make his 224 in 3 box. To help construct the box, he decided to cut
Slav-nsk [51]

Answer:

Part 1; The volume of the box Thomas wants to make is 224 = 2·w² + 12·w

Part 2; The zeros for the equation of the function, are w = -14, or w = 8

Part 3

The width of the box is 8 inch

The length of the box, is 14 inches

The height of the box, is given as 2 inches

Part 4

Please find attached the graph of the function

Step-by-step explanation:

Part 1

The volume of the box Thomas wants to make, V = 224 in.³

The dimensions he cuts out from the length and width = 2 in² each

The length of the box = 6 inches + The width of the box

Let <em>l</em> represent the length of the box and let <em>w</em> represent the width of the box, we have;

l = 6 + w

The height of the box, h = The length of the cut out square = 2 inches

The volume of the box, V = Length, l × Width, w × Height, h

∴ V = l × w × h

l = 6 + w, h = 2

∴ V = (6 + w) × w × 2

V = 2·w² + 12·w,

The equation of the volume of the box, V = 2·w² + 12·w, where, V = 224

∴ 224 = 2·w² + 12·w

Part 2

The zeros of the equation for the volume of the box, V = 2·w² + 12·w, where, V = 224 are found as follows;

V = 224 = 2·w² + 12·w

∴ 2·w² + 12·w - 224 = 0

Dividing by 2 gives;

(2·w² + 12·w - 224)/2 = w² + 6·w - 112 = 0

∴ (w + 14) × (w - 8) = 0

The zeros for the equation of the function, are w = -14, or w = 8

Part 3

We reject the value, w = -14, therefore, the width of the box, w = 8 inch

The length of the box, l = 6 + w

∴ l = 6 + 8 = 14

The length of the box, l = 8 inches

The height of the box, <em>h</em>, is given as h = 2 inches

Part 4

The graph of the function created with MS Excel is attached

4 0
3 years ago
Statements that are true for a cylinder with radius r and height h.
vampirchik [111]

Answer:

Only the second and third statements are correct:

Doubling <em>r</em> quadruples the volume.

Doubling <em>h</em> doubles the volume.

Step-by-step explanation:

The volume of a cylinder is given by:

\displaystyle V=\pi r^2h

We can go through each statement and examine its validity.

Statement 1)

If the radius is doubled, our new radius is now 2<em>r</em>. Hence, our volume is:

\displaystyle V=\pi (2r)^2h=4\pi r^2h

So, compared to the old volume, the new volume is quadrupled the original volume.

Statement 1 is not correct.

Statement 2)

Using the previous reasonsing, Statement 2 is correct.

Statement 3)

If the height is doubled, our new height is now 2<em>h</em>. Hence, our volume is:

V=\pi r^2(2h)=2\pi r^2h

So, compared to the old volume, the new volume has been doubled.

Statement 3 is correct.

Statement 4)

Statement 4 is not correct using the previous reasonsing.

Statement 5)

Doubling the radius results in 2<em>r</em> and doubling the height results in 2<em>h</em>. Hence, the new volume is:

V=\pi (2r)^2(2h)=\pi (4r^2)(2h)=8\pi r^2h

So, compared to the old volume, the new volume is increased by eight-fold.

Statement 5 is not correct.

7 0
3 years ago
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