Ask question

Ask question

All categories

3 years ago

10

What's -54 divided by 104 ?

2 answers:

Agata [3.3K]3 years ago

7 0

The answer is 0.52 for a more simple explanation

tatuchka [14]3 years ago

6 0

Your answer is -0.51923077

You might be interested in

-5x+2y=6<br> -x+2y=-2 <br> what is the solution to the system of equations?

dybincka [34]

Step-by-step explanation:

$- 5x + 2y = 6 \\ - x + 2y = - 2 \\ \\ - 5x + 2y - ( - x + 2y) = 6 - ( - 2) \\ - 5x + 2y + x - 2y = 6 + 2 \\ - 4x = 8 \\ \frac{ - 4x}{ - 4} = \frac{8}{ - 4 } \\ x = (- 2) \\ \\ -5x + 2y = 6 \\ - 5 \times - 2 + 2y = 6 \\ 10 + 2y = 6 \\ 2y = 6 - 10 \\ 2y = - 4 \\ \frac{2y}{2} = \frac{ - 4}{2} \\ y = - 2 \\ now \: lets \: see \: whether \\ this \: equation \: is \: correct. \\ - x + 2y = - 2 \\ - ( - 2) + 2 \times - 2 = - 2 \\ 2 + 2 \times - 2 = - 2 \\ 2 - 4 = - 2 \\ - 2 = - 2 \\ yes \: this \: equation \: is \\ correct.$

7 0

2 years ago

1/2 (16x + 20) <br> Need help

KATRIN_1 [288]

Answer: let's say x = 1

16 x 1 =16

16+20=36

36x1/2=18

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What is the y - intercept for y=4-2x

Alexus [3.1K]

0,4 hope that helps

7 0

2 years ago

What do i multiply 36 by to get 24

Yuri [45]

Answer:

its impossible without getting a negative number

Step-by-step explanation:

5 0

2 years ago

If you want to be 95% confident of estimating the population mean to within a sampling error of plus or minus3 and the standard

Aleksandr [31]

Answer:

The sample size required is at least 171

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What sample size is required?

A samle size of at least n is required, in which n is found when $M = 3, \sigma = 20$

So

$M = z*\frac{\sigma}{\sqrt{n}}$

$3 = 1.96*\frac{20}{\sqrt{n}}$

$3\sqrt{n} = 20*1.96$

$\sqrt{n} = \frac{20*1.96}{3}$

$(\sqrt{n})^{2} = (\frac{20*1.96}{3})^{2}$

$n = 170.7$

Rouding up

The sample size required is at least 171

5 0

2 years ago