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krok68 [10]
3 years ago
12

Malik deposited 1050 in a savings account and it earned 241.50 in simple interest after four years. Find the interest after four

years. Find the interest rate on malik's savings account
Mathematics
1 answer:
kap26 [50]3 years ago
7 0

Answer:

if it's true simple interest then each year's interest is the same so interest for one year is a quarter of 241.50 which give you the rate but if each year's interest in left in the account the result will be different , it is a really poorly worded question



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Simplify the following expression. 3x ^ 4 + 2x ^ 3 - 5x ^ 2 + 4x ^ 2 + 6x - 2x - 3x ^ 4 + 7x ^ 5 - 3x ^ 3
hammer [34]

Answer:

7x ^ 5  - x ^ 3- x ^ 2 + 4x

Step-by-step explanation:

1) 3x ^ 4 + 2x ^ 3 - 5x ^ 2 + 4x ^ 2 + 6x - 2x - 3x ^ 4 + 7x ^ 5 - 3x ^ 3

Rearrange the expression.

2) 7x ^ 5+3x ^ 4- 3x ^ 4 + 2x ^ 3  - 3x ^ 3- 5x ^ 2 + 4x ^ 2 + 6x - 2x

Solve.

3) 7x ^ 5  - x ^ 3- x ^ 2 + 4x

4 0
3 years ago
Express each number as a quotient of two integer of 54
inysia [295]
  <span>There are many possibilities. For example 108/2, -108/-2, 162/3, -162/-3, 216/4, -216/-4, and so forth....</span>
6 0
3 years ago
PLS HELP PLSSSSS PLSSSSSS PLSSSSSSSS PLSSSSSSSSSSSSSS HIRRRYYYYYYYYYYYYYYYYYYYYYYYY
qwelly [4]

Answer:

74

Step-by-step explanation:

the top two are 5 cm each angled sides and it completely added up to 74

5 0
3 years ago
How do I solve systems of equations? I was absent and the test is next week!
MrRa [10]
Well, there are three different ways to solve systems of equations:
a) Graphing
b) Substitution
c) Elimination

Graphing:
If your system of equations are written in slope-intercept form (y=mx+b "m" being the slope and "b" being the y-intercept) its quite easy.
The y-intercept is pretty much where your line touches the y-axis so if your first equation is: y=3x-2 then you will put your first point on (0,-2). Then from that point you follow the slope. if the slope is 3 then you'll rise 3 and run 1 (go three times up and one to the right and put your point right there) till you feel you have enough points to make a line. You do the same process with your second equation.

Substitution:
This is best when you have a system of equations in which an equation tells you what x or y are equal to. For example: if I have "4x+2=y" and "2y+3x= 26" you can "replace" your "2y" with the equation "4x+2=y" which gives you a brand new equation: " 2(4x+2)+3x=26". To solve this you do the distributive property and link like terms which gives you the equation "11x+4=26". Then you solve like a normal equation, isolating x and then you'll get the value of x (in this case x=2). Now you go to the first equation "4x+2=y" and replace "x" to its value (in this case it's 2) and you get y (in this example, y=10).

Elimination:
I think this one is one of the easiest methods. Let's say my systems of equations is "5x-6y=-32" & "3x+6y=48". If you take a look at y's coefficients, you see they are the same. So you can "cancel them out" like this:
      5x-6y=-32
   + 3x+6y=48
-----------------------
     8x=16  <-------- when you get this, you can solve like a normal equation
       x=2

Also, if you have, for example:
2x+6y=190 & 2x+3y=130
You can solve this by: canceling x or multiplying the second equation by 2 and canceling y.
I'm gonna show you how to do the second way (multiplying and canceling y)
My second equation is "2x+3y=130". To get an equivalent equation, I just have to multiply the whole equation by any number. If I want to cancel y, then I have to multiply by 2.
So "2x+3y=130" turns into "4x+6y=260"
Now you follow the same procedure as before:
            2x+6y=190
       -    4x+6y=260
-------------------------------
      -2x= -70
       2x=70--------> x=35
Then you pretty much follow the substitution method by replacing "x" to "35" in one of the equations.

        Hope this covers all you missed in class. If you have any questions you can comment them here or message me. :D Good luck in your exam!!!

5 0
3 years ago
If f(x) = 7+ 4x and g(x) = 1/2,
olchik [2.2K]

270

<h3>Further explanation</h3>

<u>Given:</u>

  • \boxed{ \ f(x) = 7 + 4x \ }
  • \boxed{ \ g(x) = \frac{1}{2x} \ }

<u>Question:</u>

What is the value of \boxed{ \ \bigg( \frac{f}{g} \bigg)(5)? \ }

<u>The Process:</u>

The form of \boxed{ \ \bigg( \frac{f}{g} \bigg)(x) \ } means that f(x) is divided by g(x).

\boxed{\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) \ } \rightarrow \boxed{ \ \frac{f(x)}{g(x)} \ }}

Let us solve the problem.

\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) = \frac{7 + 4x}{\frac{1}{2x}} \ }

\boxed{ \ \bigg( \frac{f}{g} \bigg)(x) = (7 + 4x) \times \frac{2x}{1} \ }

Thus, we get \boxed{{ \ \bigg( \frac{f}{g} \bigg)(x) = 14x + 8x^2 \ }}

And now, we can calculate the value of \bigg( \frac{f}{g} \bigg)(5).

\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = 14(5) + 8(5)^2 \ }

\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = 70 + 200 \ }

Thus, the value is 270.

- - - - - - - - - - -

Alternative thinking

\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = \frac{7 + 4(5)}{\frac{1}{2(5)}} \ }

\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = (7 + 20) \times 10} \ }

\boxed{\boxed{ \ \bigg( \frac{f}{g} \bigg)(5) = 270 \ }}

<h3>Learn more</h3>
  1. If f(x) = x² – 2x and g(x) = 6x + 4, for which value of x does (f o g)(x) = 0? brainly.com/question/1774827
  2. Solve for the value of the function composition brainly.com/question/2142762
  3. If g(x) is the inverse of f(x), what is the value of f(g(2)) brainly.com/question/1517760

Keywords: if, f(x), g(x), function, divide by, the value, (f/g)(5), 5, 270

#learnwithBrainly

5 0
3 years ago
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