Yes you are correct.........
Answer:
a) 6.68th percentile
b) 617.5 points
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

a) A student who scored 400 on the Math SAT was at the ______ th percentile of the score distribution.



has a pvalue of 0.0668
So this student is in the 6.68th percentile.
b) To be at the 75th percentile of the distribution, a student needed a score of about ______ points on the Math SAT.
He needs a score of X when Z has a pvalue of 0.75. So X when Z = 0.675.




Answer:
Option 2
Step-by-step explanation:
Let's say that Phalicia opens her savings account one year (12 months) before she goes to college.
With Option 1, she would have saved 300 + 50 * 11 = $850. We do 50 * 11 and not 50 * 12 because she deposits $50 for 11 months, not 12.
With Option 2, she would have saved 5 * 3¹¹ = $885735. Note that we do 3¹¹ and not 3¹² because 5 is being tripled 11 times.
Obviously, she should choose Option 2 because she saves A LOT more money.
Additionally, we can notice that Option 1 is an example of an arithmetic sequence whereas Option 2 is an example of a geometric sequence. Their explicit formulas would be aₙ = 50n + 250 and aₙ = 5 * 3⁽ⁿ⁻¹⁾ respectively.
If you divide decimals you have to bring up the decimal point but if you divide whole numbers you dont have any decimal points so you just divide the numbers. Sorry if i didnt help i just wanted to help.
Answer: 18 gallons.
Step-by-step explanation:
Let's call the total gallons that the container can hold <em>x.</em>
<em> </em>Then, based on the information given in the problem, you can write the following expression:

Now, you must solve for x, as you can see below. Therefore, you obtain the following result:
