All categories

2 years ago

How do you find out if 5/4 is greater or less than 7/4

Mathematics

2 answers:

castortr0y [4]2 years ago

8 0

Answer: 7/4 is greater

Step-by-step explanation: If you divide 7 by 4 you get 1.75. Then you divide 5 by 4 and you get 1.25. 1.75 is greater than 1.25. Also, if they have the same denominator, whichever has a higher numerator would be greater.

serious [3.7K]2 years ago

6 0

First off, 7/4 has more 4ths than 5/4 so that is greater, but second, you can convert the numbers into decimals, I can't remember how but by doing that you can have an easier way to compare them.

Hope this helps, if not, comment below please!!!!

You might be interested in

Help on number 8 please!

solmaris [256]

Answer:

ab/3

Step-by-step explanation:

I don't really know how to explain.

Μα†hway

hope this helps!

5 0

1 year ago

Read 2 more answers

The expression c- 0.25c can be used to find the cost of an item on sale for 25% off. Which expression below is equivalent to c-

Usimov [2.4K]

Answer:

0. 33 por que los jamones sivieron a 15 pesos y mi mama se va asta otro lado para compralo

6 0

2 years ago

Find f'(x) for f(x) = cos^2(3x^3).

garik1379 [7]

$f(x) = \cos^2(3x^3)\\f'(x) = \frac{d}{dx}[\cos^2(3x^3)]\\= 2\cos(3x^3) \cdot \frac{d}{dx}[cos(3x^3)]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot \frac{d}{dx}[3x^3]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot 9x^2\\= -18x^2\cos(3x^3)\sin(3x^3)$

6 0

2 years ago

A survey conducted by a leading HMO found that of 2000 women, 340 were heavy smokers and 25 had emphysema. Of those who had emph

belka [17]

Answer:

The events being a heavy smoker and having emphysema are not independent.

Step-by-step explanation:

We are given the following in the question:

Number of women = 2000

Number of heavy smoker = 340

Number of women who has emphysema = 25

Number of women who has emphysema and are heavy smoker = 21

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

P(Smoker) =

$P(S) = \dfrac{340}{2000}=0.17$

P(emphysema) =

$P(E) = \dfrac{25}{2000}= 0.0125$

P(Smoker and emphysema) =

$P(S\cap E) = \dfrac{21}{2000} = 0.0105$

Two events A and B are said to be independent if

$P(A\cap B)=P(A)\times P(B)$

Checking conditions for independence:

$P(S)\times P(E) = 0.17\times 0.0125=0.002125\\P(S)\times P(E) \neq 0.0105\\P(S)\times P(E)\neq P(S\cap E)$

Thus, the events being a heavy smoker and having emphysema are not independent.

3 0

2 years ago

What is the solution to the equation 5(x-6)=2(x+3)?

Tanzania [10]

Distribute first
5x-30=2x+6
add 30 to both sides of the equation
5x=2x+36 (the -30 cancels out)
subtract 2x from both sides
3x=36
divide both sides by 3
x=12

4 0

2 years ago

Read 2 more answers