3 years ago

1. sin(x+20) = cos(2x+10) 2. sin (2x+14) = cos(x-5)

Mathematics

1 answer:

lakkis [162]3 years ago

3 0

Answer:

x=20°

x=27°

Step-by-step explanation:

sin(x+20)=cos (2x+10)

=sin (90-(2x+10))

so x+20=90-(2x+10)

x+20+2x+10=90

3x=90-30

3x=60

x=60/3=20

2x+14+x-5=90

3x+9=90

3x=90-9=81

x=81/3=27

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In triangle $ABC,$ point $D$ is on $\overline{AC}$ such that $AD = 3CD = 12$. If $\angle ABC = \angle BDA = 90^\circ$, then what

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see the attached figure to better understand the problem

Triangles ABD and BCD are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

$\frac{BD}{AD}=\frac{CD}{BD}$

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