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Kryger [21]
3 years ago
12

I need help filling in the blank

Mathematics
1 answer:
Rudik [331]3 years ago
6 0
The basic format for an exponential equation is y=ab^x

You know the Initial value is 16 and the decay constant is 0.5:

y=16x0.5^x

Percent increased by: 0.5/16 x 100%
=3.125% 

I have attached the graph below. 

Sample problem: 
Scientists started with an unknown sample. They weighed 16 grams of it. They noticed soon after that the sample was decaying at the speed of 0.5 grams every year. Model an equation. 

Hope I helped :) 

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she has 2 1/2 cups of peanuts. 3 1/4 cups of rainsins and 2 2/3 cups of banana chips. how many cups of trail mix can she make
andriy [413]

Answer:

8 cups of trail mix

Step-by-step explanation:

2 1/2 + 3 1/4 + 2 2/3= 8 5/12

6 0
3 years ago
Read 2 more answers
Use trigonometric substitution to evaluate the integral 13 + 12x − x2 dx . First, write the expression under the radical in an a
SCORPION-xisa [38]

I don't see a square root sign anywhere, so I'll assume the integral is

\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx

First complete the square:

13+12x-x^2=49-(6-x)^2=7^2-(6-x)^2

Now in the integral, substitute

6-x=7\sin t\implies\mathrm dx=-7\cos t\,\mathrm dt

so that

t=\sin^{-1}\left(\dfrac{6-x}7\right)

Under this change of variables, we have

7^2-(6-x)^2=7^2-7^2\sin^2t=7^2(1-\sin^2t)=7^2\cos^2t

so that

\displaystyle\int\sqrt{13+12x-x^2}\,\mathrm dx=-7\int\sqrt{7^2\cos^2t}\,\cos t\,\mathrm dt=-49\int|\cos t|\cos t\,\mathrm dt

Under the right conditions, namely that cos(<em>t</em>) > 0, we can further reduce the integrand to

|\cos t|\cos t=\cos^2t=\dfrac{1+\cos(2t)}2

\displaystyle-49\int|\cos t|\cos t\,\mathrm dt=-\frac{49}2\int(1+\cos(2t))\,\mathrm dt=-\frac{49}2\left(t+\frac12\sin(2t)\right)+C

Expand the sine term as

\dfrac12\sin(2t)}=\sin t\cos t

Then

t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \sin t=\dfrac{6-x}7

t=\sin^{-1}\left(\dfrac{6-x}7\right)\implies \cos t=\sqrt{7^2-(6-x)^2}=\sqrt{13+12x-x^2}

So the integral is

\displaystyle-\frac{49}2\left(\sin^{-1}\left(\dfrac{6-x}7\right)+\dfrac{6-x}7\sqrt{13+12x-x^2}\right)+C

3 0
3 years ago
Can someone help me please i am so confused and its due today!!
deff fn [24]

Answer:

x is 20

Step-by-step explanation:

7 0
3 years ago
Simplify the expression. (15 + 8)[23 – (10 + 7)]
wariber [46]
(23)(23-17)
(23)(6)
138
3 0
3 years ago
It says to find the area of the figure but I have no idea what to do
Westkost [7]
2.5 is also on the top and try multiplying 2.5 and 10
6 0
3 years ago
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