Hi the answer is y=mx+ b10
Answer:
it's a /
Step-by-step explanation:
Answer:
34
Step-by-step explanation:
5+(-8)+0+37
5-8+37
34
Answer:
DL/dt = 529 miles/h
Step-by-step explanation:
The radio station (point A) the point just up the radio station ( point B), and the variable position of the plane ( at specif t point C) shape a right triangle wich hypothenuse L is:
L² = d² + x²
d is the constant distance between the plane and the ground
Then differentiation with respect to time on both sides of the equation
2*L*dL/dt = 2*d* Dd/dt + 2*x*dx/dt
But Dd/dt = 0
L*dL/dt = x*dx/dt
x = 5 miles dx/dt = 570 m/h L = √ d² + x² L √ (5)² + (2)²
L = √29 L = 5.39 m
5.39 *DL/dt = 5*570 m/h
DL/dt = 5*570/5.39 miles/h
DL/dt = 528.76 miles/h
DL/dt = 529 miles/h
Answer:
![g(x)=\sqrt[3]{x}-5](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-5)
Step-by-step explanation:
Consider the given function is
![f(x)=\sqrt[3]{-2x+4}-5](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B-2x%2B4%7D-5)
It is given that 
and neither g(x) nor h(x) is solely x.
![f(x)=\sqrt[3]{(-2x+4)}-5](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B%28-2x%2B4%29%7D-5)
Let , then we get
![f(x)=g(h(x))=\sqrt[3]{h(x)}-5](https://tex.z-dn.net/?f=f%28x%29%3Dg%28h%28x%29%29%3D%5Csqrt%5B3%5D%7Bh%28x%29%7D-5)
Substitute h(x)=x in the above function.
Therefore, the required functions are and .
Check the solutions.
![[\because h(x)=-2x+4]](https://tex.z-dn.net/?f=%5B%5Cbecause%20h%28x%29%3D-2x%2B4%5D)
![g(h(x))=\sqrt[3]{-2x+4}-5](https://tex.z-dn.net/?f=g%28h%28x%29%29%3D%5Csqrt%5B3%5D%7B-2x%2B4%7D-5)
![[\because g(x)=\sqrt[3]{x}-5]](https://tex.z-dn.net/?f=%5B%5Cbecause%20g%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-5%5D)
Therefore, our solution is correct.
