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3 years ago

A car is driving at 40 kilometers per hour. How far, in meters, does it travel in 2 seconds?

Mathematics

2 answers:

Troyanec [42]3 years ago

6 0

Answer:

i think its 22.22 thats my guess

Tasya [4]3 years ago

6 0

Answer:

$\frac{1}{45}$ kilometers

Step-by-step explanation:

60 minutes = 3600 seconds

$\frac{40}{3600} =\frac{y}{2}$

3600y = 80

3600y ÷ 3600 = 80 ÷ 3600

$y=\frac{1}{45}$

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Lina20 [59]

Answer:

Step-by-step explanation:

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3 years ago

One side of a rectangle is 3 inches shorter than the other side, and the perimeter is 54 inches. What are the dimensions

vodomira [7]

Answer:

2(x-3)+2x=54

Step-by-step explanation:

Take the side length of the rectangle as x

For the perimeter we must have - as we also have 2 lots of a side that is 3 inches shorter than x.

$2x + 2(x-3) = 54$

8 0

3 years ago

M is the midpoint of CD. Given the coordinates of one endpoint C(10,-5) and the midpoint M(4, 0), find the coordinates of the ot

mash [69]

Answer:

D(-2, 5).

Step-by-step explanation:

We are given that M is the midpoint of CD and that C = (10, -5) and M = (4, 0).

And we want to determine the coordinates of D.

Recall that the midpoint is given by:

$\displaystyle M = \left(\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2}\right)$

Let C(10, -5) be (x₁, y₁) and Point D be (x₂, y₂). The midpoint M is (4, 0). Hence:

$\displaystyle (4, 0) = \left(\frac{10+x_2}{2} , \frac{-5+y_2}{2}\right)$

This yields two equations:

$\displaystyle \frac{x_2 + 10}{2} = 4\text{ and } \frac{y_2 - 5}{2} = 0$

Solve for each:

$\displaystyle \begin{aligned}x_2 + 10 &= 8 \\ x_2 &= -2 \end{aligned}$

And:

$\displaystyle \begin{aligned} y_2 -5 &= 0 \\ y_2 &= 5\end{aligned}$

In conclusion, Point D = (-2, 5).

5 0

3 years ago

Help me solve this question

german

Answer:

700 feet

Step-by-step explanation:

you just add the two 50 wich makes that 100 then add 100 to 600

6 0

3 years ago

A bag of concrete equals 1000 cu. Inches. Your customer already has 2 bags at home. How many more bags does he need to fill an a

adelina 88 [10]

From the information given;
1 bag of concrete = 1000 in^3
2 bags at home = 1000*2 = 2000 in^3

The available space has a volume of;

Volume = (5*12)*10*10 (Note: 1 ft = 12 inches)
Volume = 60*10*10 = 6000 in^3

The remaining volume = Available space - occupied space = 6000 - 2000 = 4000 in^2

1 bag = 1000 in^3
x bags = 4000 in^2

Then,
x = 1*4000/1000 = 4 bags.
This means 4 more bags of concrete will be required to fully fill the space.

5 0

3 years ago