Ask question

Ask question

All categories

3 years ago

10

A school ice hockey game has three 20-minute periods. Collin plays 12 minutes each period. Which ratio represents Collin's playi

ng time compared to the total number of minutes of playing time possible?

1 answer:

Korvikt [17]3 years ago

3 0

Answer: 36:60

Step-by-step explanation:

3x20=60,3x12=36

You might be interested in

How to solve -5 + 13y = -7

zubka84 [21]

Answer:

y = -2/13

Step-by-step explanation:

-5 + 13y = -7

Add 5 to each side

-5+5 + 13y = -7+5

13y = -2

Divide by 13

13y/13 = -2/13

y = -2/13

5 0

3 years ago

Read 2 more answers

What is 0.95 rounded off to the nearest whole number

mihalych1998 [28]

1.00 would be your answer because 95 rounded up is 100. So, 0.95 is closest to 1.00

8 0

3 years ago

The oldest child in a family of four children is twice as old as the yougest. The two middle children are 12 and 16 years old. I

Vladimir [108]

Four children average is 15.25 so ages must add to 61
61-12-16=33
11 and 22 go into 33
Youngest is 11

6 0

2 years ago

B(n)=−4−2(n−1)<br> What's the 12th term in the sequence?

marysya [2.9K]

The 12th term in the sequence is -26.

Given,

B (n) = -4 – 2(n – 1)

We have to find the 12th term in the sequence:

To find the nth term in an arithmetic sequence:

An arithmetic sequence's nth term is determined by the formula a = a + (n - 1)d. The common difference, or d, is the difference between any two consecutive terms in an arithmetic series; it can be calculated by deducting any pair of terms starting with a and an+1.

Here,

First term, a = -4

Common difference, d = -2

nth term = 12

Now, let’s find 12th term

B(n) = -4 -2(n – 1)

B(12) = -4 – 2(12 – 1)

B(12) = -4 -2(11)

B(12) = -4 -22

B(12) = -26

That is, the 12th term in the sequence is -26.

Learn more about arithmetic sequence here:

brainly.com/question/11570734

#SPJ1

8 0

1 year ago

Which of the following is NOT a linear factor of the polynomial function?

Natalija [7]

Answer:

Among the four choices, $(x + 5)$ is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let $a$ denote some constant. A linear factor of the form $(x - a)$ is a factor of a polynomial $f(x)$ if and only if $f(a) = 0$ (that is: replacing all $x$ in the polynomial $f(x) \!$ with the constant $a\!$ would give this polynomial a value of $0$ .)

For example, in the second linear factor $(x - 2)$ , the value of the constant is $a = 2$ . Verify that the value of $f(2)$ is indeed $0$ . (In other words, replacing all $x$ in the polynomial $f(x) \!$ with the constant $2$ should give this polynomial a value of $0\!$ .)

$\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}$ .

Hence, $(x - 2)$ is indeed a linear factor of polynomial $f(x)$ .

Similarly, it could be verified that $(x - 5)$ and $(x + 2)$ are also linear factors of this polynomial function.

Rewrite the first linear factor $(x + 5)$ in the form $(x - a)$ for some constant $a$ : $(x + 5) = (x - (-5))$ , where $a = -5$ .

Calculate the value of $f(5)$ .

$\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}$ .

$f(5) \ne 0$ implies that $(x - (-5))$ (which is equivalent to $(x + 5)$ ) isn't a linear factor of this polynomial function.

3 0

2 years ago