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Montano1993 [528]
3 years ago
7

tell whether this has one solution, infinitely many solutions, or no solution. Explain your reasoning. y=2x+7, y=3x-1

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer:

One solution

Step-by-step explanation:

They have isolated y for you in both equations so you can plug either one into the other.

y = 3x - 1

2x + 7 = 3x - 1

isolate the x

7 = x - 1

x = 8

Go back to the original and plug 8 into x to get y.

y = 2 (8) + 7

y = 16 + 7

y = 23

This means at (8, 23) y = 2x+7 is equal to y = 3x-1. In other words they share a point at (8, 23). This is the only solution because for any other x and y they'd not be equal.

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Addison had 560 blue marbles and 279 red marbes . How many fewer red marbles does she have then blue
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281

Step-by-step explanation:

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What is compatible to 428
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Any number but 0 is compatible because you can add any number to 428.
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X^2− 14 + 45 = 0<br> Solve with quatratics formula
bulgar [2K]

Step-by-step explanation:

-b√b²-4(ac)

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6 0
3 years ago
The cost of controlling emissions at a firm is given by:
shepuryov [24]

Answer:

The correct answer is 0.5 pounds of pollutant.

Step-by-step explanation:

According to the problem the cost of controlling emissions at a firm is given by:

C(q) = 1,260 + 100 × q^{2} , where q is the reduction in emissions (in pounds of pollution per day) and C is the daily cost to the firm (in dollars) of this reduction.

Government clean-air subsidies amount to $100 per pound of pollutant removed per day.

Net cost = C(q) - Subsidy

⇒ Net Cost = 1,260 + 100 × q^{2} - 100 × q.

In order to minimize net cost we calculate,  \frac{d}{dq}(Net cost) = 0.

⇒ 200 × q - 100 = 0

⇒ q = 0.5

We can see that the second order derivative is positive and thus the net cost minimizes.

Thus the firm should remove 0.5 pounds of pollutant each day in order to minimize net cost.

5 0
3 years ago
F(x)=x^3+ax^2+bx+3 where a and b are constants. bx Given that when f (x) is divided by (x+2) the remainder is 7, (a) show that 2
Vlad1618 [11]
Part I - First synthetic division

You need to use synthetic division to come up with an expression for a and b:

(x + 2) is a factor, and the remainder is 7, so we can draw a synthetic division table...

coefficients = 1 for X^3; A for X^2; B for X^1; and 3

-2  |        1          A            B                 3
     
                        -2        -2(A-2)          4(A-2)-2B
 
            1        (A-2)    -2(A-2)+B      4(A-2)-2B + 3  
                            
                                    Remainder = 7

<u>So...</u>

4(A-2)-2B + 3 = 7

4 * (A - 2) - 2B + 3 = 7

4A - 8 - 2B =  4

4A - 2B      = 12

2A - B = 6
Proved

-------------------------------------------------------------------------------------------------------------------
Part II - Second Synthetic Division

We draw another synthetic division table, this time with (x - 1), so the number on the left hand side will be +1

1  |        1          A            B                 3
     
                        1         (A+1)         A+B+1
 
             1      (A+1)      A+B+1       A+B+4 
                            
                                    Remainder = 4

<u>So...</u> 

A + B + 4 = 4

A + B = 0

<u>A = -B
</u>

-------------------------------------------------------------------------------------------------------------------
Part III - Solving for A and B with our two simultaneous equations

We know that<u> </u><u>A = -B</u><u /> and we also know that 2A - B = 6

Since we know that A is equal to -B We can substitute in A for -B, to get:

2A - B = 6

Therefore...

2A + A = 6

3A = 6

<u>A = 2</u>

Again, as we know that A = -B, and as we have found that A = 2, we can see:

A = -B

Therefore...

2 = -B

<u>B = -2
</u>
So our final answer is <u>A = 2, B = -2</u><u />

Hopefully this answer is more useful than the last one, and isn't so confusing!

8 0
3 years ago
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