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3 years ago

9

Write and solve a real world word problem in which there are 3 tables for every 8 chairs

2 answers:

Hoochie [10]3 years ago

8 0

Answer with explanation:

We have to Write a real world problem in which there are 3 tables for every 8 chairs.

Question

In a Company, there are computers placed on tables.There are 9 Computers on 3 Tables.And 8 chairs are Placed in front of Each Computer.Among 9 Computers there is a SuperComputer.The One Super computer is attatched with these 8 Computers.Find total number of Chairs , tables and Computers in the Room.

Solution

Total number of Chairs ,tables and Computers in the Room

=9 Computers +3 tables +8 Chairs

=20 Commodity

Mila [183]3 years ago

7 0

You multiply 3 times 8 and you get 24

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The balance in Victor's savings account went from $80 to $120. By what percentage

Nookie1986 [14]

Answer:

50%

Step-by-step explanation:

To find the percent increase, divide the increase by the original value.

The increase is $40.

The original value is $80.

40÷80 = 0.5

0.5 ⇒ 50%

It is a 50% increase.

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4 years ago

Janelle ate 4/5 of her graham cracker. Paul ate 3/5 of his graham cracker. The graham crackers were the same size.

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3 years ago

Plz help me with this. Thank you!

Tresset [83]

Answer:

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Step-by-step explanation:

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3 years ago

The histogram shows the distribution of hurricanes that have hit a country from 1851 through 2015, where 1 is the weakest level

aleksandrvk [35]

Answer:

a) mean = 0.2

variance = 0.0391

standard deviation = 0.198

b) The average hurricane is aprox. category 2.* (B)

Step-by-step explanation:

In order to find the mean, variance, and standard deviation, let us for a table for the data:

level x

1 0.411

2 0.278

3 0.221

4 0.080

5 0.010

Calculating the mean ( $\bar{x}$ )

$\bar{x} = \frac{x_1+x_2+x_3+x_4 + x_5}{n}\\\\\bar{x} = \frac{0.411 + 0.278 + 0.221 + 0.080 + 0.010}{5}\\\bar{x} = \frac{1}{5}\\ \bar{x} = 0.2$

∴Mean = 0.2

level x $x- \bar{x}$ $(x - \bar{x})^2$

1 0.411 0.211 0.0445

2 0.278 0.078 0.0608

3 0.221 0.021 0.000441

4 0.080 -0.12 0.0144

5 0.010 -0.19 0.0361

$\sum(x - \bar{x})^2 = 0.1562$

$variance = \frac{\sum(x - \bar{x})^2}{n-1} \\variance = \frac{0.1562}{4} \\variance = 0.0391$

standard deviation = √(variance)

Standard deviation = √(0.0391)

Standard deviation = 0.198

b) the average hurricane is aprox. category 2 (B)

8 0

4 years ago

I need help with #2 and 3, any help?

Setler [38]

2) y=mx+b
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6 0

4 years ago

Read 2 more answers