Ask question

Ask question

All categories

SCORPION-xisa [38]

3 years ago

13

What causes friction between two solid forces? After the roughness of the surfaces, what most affects the frictional force exper

ienced

1 answer:

Sveta_85 [38]3 years ago

7 0

Friction is caused by two solids rubbing together quickly.

You might be interested in

What do you neEnter the word that best completes the sentence.

Morgarella [4.7K]

I think it would be eager

5 0

3 years ago

What is the on ohooke benden

-Dominant- [34]

Answer:Work is the energy required to move an object from one point to another. while power is the energy transferred per unit time.

6 0

3 years ago

51. Which two of the resistor arrangements below

blsea [12.9K]

Answer:

(2) B and C

Explanation:

In B resistors are parallel

so

1/R = 1/R1 + 1/R2

= 1/8+1/8

= 2/8

so

R = 4 ohms

In C resistors are in series

so,

R= R1+R2

= 2+2

= 4

3 0

4 years ago

A thin walled spherical shell is rolling on a surface. What

ExtremeBDS [4]

Answer:

$=\frac{1/3}{5/6} = 0.4$

Explanation:

Moment of inertia of given shell $= \frac{2}{3} MR^2$

where

M represent sphere mass

R -sphere radius

we know linear speed is given as $v = r\omega$

translational $K.E = \frac{1}{2} mv^2 = \frac{1}{2} m(r\omega)^2$

rotational $K.E = \frac{1}{2} I \omega^2 = \frac{1}{2} \frac{2}{3} MR^2 \omega^2$

total kinetic energy will be

$K.E = \frac{1}{2} m(r\omega)^2 + \frac{1}{2} \frac{2}{3} MR^2 \omega^2$

$K.E =\frac{5}{6} MR^2 \omega^2$

fraction of rotaional to total K.E

$=\frac{1/3}{5/6} = 0.4$

8 0

3 years ago

How much force is needed to accelerate a bicycle and rider with a total mass of 50 kg at a rate of 2.0 m/s2 ?

True [87]

Answer:

The answer is D 100 newton

Explanation:

2.0m/s2 is d acceleration while the 50kg is the mass. Force = mass x acceleration. So f=50x2.so force is 100 newton

8 0

3 years ago