How does the radius of a string affect centripetal force.

Determine whether each phrase describes speed or velocity. The displacement of an object during a specific unit of time: How fas

svet-max [94.6K]

The displacement of an object during a specific unit of time: Velocity (the direction is part of displacement.)

How fast or slow an object is moving and in what direction: Velocity (speed & direction)

How fast or slow an object is moving: Speed (no direction)

A cheetah running 97 km/h: Speed (no direction)

A train traveling 45 m/s north: Velocity (speed & direction)

8 0

3 years ago

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Explain the law of inertia in your own words.

natita [175]

A

An object at rest will remain at rest unless acted on by a force. An object in motion continues in motion with the same speed and in the same direction unless acted upon by a force.

Explanation:

6 0

3 years ago

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A 0.03-kg bullet is fired with a horizontal velocity of 470 m/s and becomes embedded in block B which has a mass of 3 kg. After

Gala2k [10]

Answer with Explanation:

We are given that

Mass of bullet, $m_1=0.03 kg$

$u_1=470 m/s$

$m_2=3 kg$

$\mu_k=0.2$

$m_3=30 kg$

We have to find the velocity of the bullet and block B after the first impact and final velocity of the carrier.

According to law of conservation of momentum

$m_1u_1=(m_1+m_2)v$

$0.03(470)=(0.03+3)v$

$v=\frac{0.03(470)}{(0.03+3)}=4.65 m/s$

Hence, the velocity of the bullet and block B after the first impact=4.65 m/s

According to law of conservation of momentum

$(m_1+m_2)v=(m_1+m_2+m_3)V$

$(0.03+3)\times 4.65=(0.03+3+30)V$

$V=\frac{(0.03+3)\times 4.65}{(0.03+3+30)}$

$V=0.43 m/s$

3 0

4 years ago

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Earth moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is kilometers, and the

serious [3.7K]

Complete question is;

Earth moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is 149,598,000 kilometers, and the eccentricity is 0.0167. Find the minimum distance (perihelion) and the maximum distance (aphelion) of Earth from the sun

Answer:

Minimum distance = 147,099,713.4 km

Maximum distance = 152,096,286.6 km

Explanation:

The formula for the eccentricity of an ellipse is given by;

e = c/a

where;

c is distance from the center of the ellipse to the focus of the ellipse.

a is distance from the center of ellipse to a vertex.

From the question, we are given;

a = 149,598,000

e = 0.0167

Thus;

0.0167 = c/149,598,000

c = 0.0167 × 149,598,000

c = 2,498,286.6

Now, formula for the minimum distance (perihelion) is;

Minimum distance = a - c

Minimum distance = 149598000 - 2498286.6

Thus;

Minimum distance = 147,099,713.4 km

Similarly, formula for the maximum distance (aphelion) is;

Max distance = a + c

Max distance = 149598000 + 2498286.6

Maximum distance = 152,096,286.6 km

4 0

3 years ago

Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to

Deffense [45]

Answer:

P2 = 128,205 pascal.

Explanation:

Given the following data;

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

$PT = K$