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AnnyKZ [126]
3 years ago
5

How does the radius of a string affect centripetal force.

Physics
1 answer:
KiRa [710]3 years ago
5 0

Answer:

because a raduis is half of 25% of a cicrle.

Explanation:

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Two resistances of 100ohms and 0 ohms were connected in parallel. What is the overall resistance
Inga [223]

Answer:

20 ohms,100*2/10=20

Explanation:

since it as to be in parallel arrangement and connected in side by side due to same p.d in a cross each resistor

6 0
3 years ago
Who ever answers Frist get marked the Brainly Est
natka813 [3]

Answer:

Explanation:

It would actually be A. 30 , as each hour of ascension (i am not sure about the correct terminology) equals 15 .

3 0
3 years ago
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A 512Hz tuning fork is used with a resonating column to determine the velocity of sound in water. If the spacing between resonan
EastWind [94]

Answer:

v= 1495.04 m/s

Explanation:

The formula for velocity of sound is given by ;

v= fλ   --------where

v= velocity of sound

f= frequency of turning fork

λ = wavelength

However,

Δ L = 1/2 λ   ------where Δ L is spacing between resonances.

1.46 = 1/2 λ

1.46 * 2 = λ

2.92 m = λ

v= fλ

v= 512 * 2.92

v= 1495.04 m/s

6 0
3 years ago
Write the electron configurations for titanium (Ti), vanadium (V), chromium (Cr), and manganese (Mn).
Tomtit [17]
See from periodic table the proton or atomic number of elements u want to know about then as u know first electron shell can hold 2 electrons 2nd can hold eight as well as all others........protons are equal to electrons so divide proton number into shells but remember to use amounts which it can hold

CHEERS !!
8 0
3 years ago
Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two
andre [41]

Answer:

197.5072.

Explanation:

According to the Coulomb's law, the magnitude of the electrostatic force of interaction between two charges \rm q_1 and \rm q_2 which are separated by the distance \rm d is given by

\rm F = \dfrac{kq_1q_2}{d^2}.

<em>where,</em> k is the Coulomb's constant.

For the case, when,

  • \rm q_1 = Q.
  • \rm q_2 = Q.
  • \rm d=r.
  • \rm F=12.3442.

Then, using Coulomb's law,

\rm 12.3442 = \dfrac{kQQ}{r^2}=\dfrac{kQ^2}{r^2}\ \ \ \ .......\ (1).

For the case, when,

  • \rm q_1 = 2Q.
  • \rm q_2 = 2Q.
  • \rm d=\dfrac r2.

Then, using Coulomb's law, the new electric force between the charges is given by,

\rm F' = \dfrac{k(2Q)(2Q)}{\left (\dfrac r2\right )^2}\\=\dfrac{k\ 4Q^2}{\dfrac{r^2}{4}}\\=4\times 4 \times \dfrac{kQ^2}{r^2}\\=16\ \dfrac{kQ^2}{r^2}\\=16\times 12.3442\ \ \ \ \ \ \ \ (Using\ (1))\\=197.5072.

8 0
3 years ago
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