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Semenov [28]
3 years ago
10

I WILL GIVE BRAINLIEST BUT PLEASE ANSWER PLEASE

Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0

Answer:

I do not know this answer. Ask "tofu0"

Step-by-step explanation:

If you need anymore help ask, Brainly. Have a nice day!

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Solve y=f(x) for x. Then find the input when the output is -3.
DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

\:\:y=\:\left(x-5\right)^3-1

-3\:=\:\left(x-5\right)^3-1\:\:\:

switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

\left(x-5\right)^3=-2

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}

And the real input is:

x=-\sqrt[3]{2}+5

  • x=3.74
4 0
3 years ago
PLZ HELP PLZ <br><br> I just need the ratio
iris [78.8K]

Answer: 8:12 and 36:54

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A number that is equal to 36 more than y
Dmitry_Shevchenko [17]
5 Hope I helped. Have a good day
6 0
3 years ago
Read 2 more answers
P(-3,6), Q(-3,-6) and R(6,-2) are the vertices of a triangle. Calculate the perimeter of this triangle.​
Eva8 [605]

Answer:

33.89

Step-by-step explanation:

the side lengths are the distances between the corner points of the triangle.

P and Q have the same x value, and they therefore create a side parallel to the y-axis. and it is easy to find the length of this side : it is just the difference of the y values.

PQ = 6 - (-6) = 6 + 6 = 12

QR and RP are trickier.

we need Pythagoras to calculate the length of the direct connection between these points as the Hypotenuse of the right triangles with the differences in x and in y values as the other sides.

QR :

QR² = (-3 - 6)² + (-6 - -2)² = (-9)² + (-4)² = 81 + 16 = 97

QR = sqrt(97) ≈ 9.848857802

RP :

RP² = (6 - -3)² + (-2 - 6)² = 9² + (-8)² = 81 + 64 = 145

RP = sqrt(145) ≈ 12.04159458

the perimeter/circumference of the triangle is the sum of all 3 sides

= 12 + sqrt(97) + sqrt(145) ≈ 33.89

3 0
3 years ago
PLEASE HELP ILL MAKE YOU THE BRAINIEST <br> Find the value of x
Firdavs [7]

Answer:

12.04

Step-by-step explanation:

add 8 and 9 by the power of two: 8^2+9^2

that equals to 145

find the square root of 145 and that equals to 12.04

4 0
2 years ago
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