You add all the money together than divide it have a good day
Answer:

Step-by-step explanation:
Given the mean is 3.2, standard deviation is 0.8 and the sample size is 64.
-We calculate the probability of a mean of 3.4 as follows:
#First determine the z-value:

#We then determine the corresponding probability on the z tables:

Hence, the probability of obtaining a sample mean this large or larger is 0.0228
Answer:
Answers in the pics
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)